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olganol [36]
2 years ago
14

Hi can someone please help me? If sin2A=cos 3A find the value of A. Can you please explain in full detail how you arrived at you

r answer? Also Find the exact value of (sec30)^2. Will I need to use a calculator in order to solve this prob?
Mathematics
1 answer:
cupoosta [38]2 years ago
6 0
<span>Sin (x) = Cos (90 - x)</span>
<span>sin(2A) = cos (90 - 2A)
=cos (3A)
90 - 2A = 3A
5A=90
A=18</span>
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Suppose you were looking at the histogram of the incomes of all of the households in the United States. Do you think that the hi
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Write a real word problem that you can solve by writing an equation the answer to the problem must be 6
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2 years ago
Question. 1 :
vovikov84 [41]
<h3>Answer to Question 1:</h3>

AB= 24cm

BC = 7cm

<B = 90°

AC = ?

<h3>Using Pythagoras theorem :-</h3>

AC^2 = AB^2 + BC ^ 2

AC^2 = 24^2 + 7^2

AC^2 = 576 + 49

AC^2 = √625

AC = 25

<h3>Answer to Question 2 :-</h3>

sin A = 3/4

CosA = ?

TanA = ?

<h3>SinA = Opp. side/Hypotenuse</h3><h3> = 3/4</h3>

(Construct a triangle right angled at B with one side BC of 3cm and hypotenuse AC of 4cm.)

<h3>Using Pythagoras theorem :-</h3>

AC^2 = AB^2 + BC ^ 2

4² = AB² + 3²

16 = AB + 9

AB = √7cm

<h3>CosA = Adjacent side/Hypotenuse</h3>

= AB/AC

= √7/4

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=BC/AB

= 3/√7

4 0
2 years ago
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