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NeTakaya
3 years ago
8

Both Dominic and Zoe are 4 feet 6 inches tall. What is their combined height in inches?

Mathematics
2 answers:
Dafna11 [192]3 years ago
7 0

Answer:

Their combined height is 108 inches

Step-by-step explanation:

1 ft = 12 inches

12 * 4 = 48 inches

48 + 6 = 54 inches

54 * 2 = 108 inches

Mariulka [41]3 years ago
5 0

Answer:

9 ft and 0 inches

Step-by-step explanation:

4 ft 6 inch + 4 ft 6 inch = 8ft 12inch

12 inches = 1 foot

8 ft + 1 ft = 9ft

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I need help with #39-42, please explain.
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For question 39 & 40, we need to use the below equation to complete the sentence

l=m\sqrt{n}

Question 39:

When ' n ' increase, the \sqrt{n} will also increase and that multiplied with constant ' m ', the l will also increase.

Solution for question 39:

As n increases and m stays constant , l <u>increases</u>

-------

Question 40:

Solving the equation for m, we get

l = m\sqrt{n} \\ \\ m=\frac{l}{\sqrt{n}}

When ' l ' increases, the numerator increase, the denominator stays constant because 'n' stays constant, for this condition, the fraction increases.

Solution for question 40:

As l increase and n stays constant, m <em><u>increases</u></em>

------

For question 41 & 42, we need to use the below equation to complete the sentence

r=s^2/t^2

Question 41:

When s is triped, the equation will be...

r=(3s)^2/t^2=\frac{3^{2}s^{2}}{t^2}   =9s^2/t^2

Solution for question 41:

If s is tripled and t stays constant, r is multiplied by <em><u>9</u></em>

--------

Question 42:

When t is doubled, the equation will be...

r=s^2/(2t)^2=\frac{s^2}{2^2 \cdot t^2}=\frac{s^2}{4t^2}\\   \\ r=0.25s^2/t^2 \; \; (or) \; \; \frac{1}{4} \cdot \frac{s^2}{t^2}

Solution for 42:

If t doubled and s stays constant, r is multiplied by <em><u>1/4 or 0.25</u></em>


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Step-by-step explanation:

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