Simplify 5 x -5 A 10 B 0 C 25 D -25

What is the value of x, when 10(x + 2) = 5(x + 8)?

olga_2 [115]

Solve for x:
10 (x + 2) = 5 (x + 8)

Expand out terms of the left hand side:
10 x + 20 = 5 (x + 8)

Expand out terms of the right hand side:
10 x + 20 = 5 x + 40

Subtract 5 x from both sides:
(10 x - 5 x) + 20 = (5 x - 5 x) + 40

10 x - 5 x = 5 x:
5 x + 20 = (5 x - 5 x) + 40

5 x - 5 x = 0:
5 x + 20 = 40

Subtract 20 from both sides:
5 x + (20 - 20) = 40 - 20

20 - 20 = 0:
5 x = 40 - 20

40 - 20 = 20:
5 x = 20

Divide both sides of 5 x = 20 by 5:
(5 x)/5 = 20/5

5/5 = 1:
x = 20/5

The gcd of 20 and 5 is 5, so 20/5 = (5×4)/(5×1) = 5/5×4 = 4:

Answer: x = 4

6 0

3 years ago

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If a baker doubles a recipe that calls for 6-2/3 cups of flour. How many cups will be needed in all?

nadya68 [22]

Hey there!

The easiest way I could think to do this is by converting your mixed number to an improper fraction and multiplying the fraction by 2, or 2 over 1.

$6 \frac{2}{3} = 6*3+2 = \frac{20}{3}$

$\frac{20}{3} * \frac{2}{1}$

To multiply fractions, you can just multiply the numerators and denominators and simplify, if applicable.

$\frac{20}{3} * \frac{2}{1} = \frac{40}{3}$

Since you can't simplify this fraction in its improper form, just convert it back into a mixed number.

$\frac{40}{3} = 13 \frac{1}{3}$

So, your answer will be $13 \frac{1}{3}$ .

Hope this helped you out! :-)

4 0

3 years ago

Read 2 more answers

Which of the following equations have no solutions?

Andre45 [30]

Answer:

A

Step-by-step explanation:

If the variable quantities are the same, but the constants are different, then that equation has no solutions.

4 0

3 years ago

If (x-y)^2=71 and x^2+y^2=59 what is the value of xy?

Lena [83]

Solve the equations
first one
take the sqrt of both sides
x-y=√71
add y to both sides
x=y+√71
sub y+√71 for x in other part

(y+√71)²+y²=59
y²+2y√71+71+y²=59
2y²+2y√71+71=59
minus 59 both sides
2y²+2y√71+12=0
factor out 2
2(y²+y√71+6)=0
use quadratic equation or something
y= $\frac{- \sqrt{71}- \sqrt{47} }{2}$ and $\frac{- \sqrt{71}+ \sqrt{47} }{2}$

sub those for x

x=y+√71
note: √71=(2√71)/2

x= $\frac{- \sqrt{71}- \sqrt{47} +2\sqrt{71}}{2}$ , $\frac{\sqrt{71}- \sqrt{47}}{2}$
or
x= $\frac{- \sqrt{71}+ \sqrt{47} +2\sqrt{71}}{2}$ , $\frac{\sqrt{71}+ \sqrt{47}}{2}$

xy= $\frac{\sqrt{71}- \sqrt{47}}{2}$ times $\frac{-\sqrt{71}- \sqrt{47}}{2}$ or $\frac{\sqrt{71}+ \sqrt{47}}{2}$ times $\frac{-\sqrt{71}+ \sqrt{47}}{2}$

the result is -6 both times

xy=-6

5 0

4 years ago

Determine the area of each polygon below Help me please

julia-pushkina [17]

9) Separate the polygon into 2 shapes (a rectangle and triangle). Then plug in the formula for those 2 shapes separately and add the 2 areas.
First, the triangle's area = bh x 1/2 or bh/2.
b=5 and h=5, so 5x5/2 or 25/2 = 12.5.
Next, solve the area for the rectangle(lw=A). l=5 and 2=8, so 5x8=40.
Add 40 +12.5 = 52.5cm^2 (always include units).

10) It is similar to the last problem. You will separate the polygon into 2 shapes (a circle and a square), but this time you will subtract the area of the sector formed from the circle (draw a dotted line where the circle would be formed in the square).
So, the area of the square is 2x2=4ft^2.
area of a circle is (pi)r2 or (pi)2^2= 4pi or about 12.5ft^2.
4+12.5 = 16.5 ft^2.
Now, the area of the sector must be subtracted from the combination of the 2 areas found above.
The area of a sector is 2(pi)r x (C/360).
The angle is given as 90°, the radius is 2 ft. Now plug these into the equation.
2(pi)(2)x(90/360) = 3.14ft^2.
16.5-3.14= 13.4 ft^2.

6 0

3 years ago