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jeyben [28]
3 years ago
5

PLEASEEE HELPPPP MEE WITH LINE PLOTSSS I DONT UNDERSTAND THISSSS PLEASEE HELPPPP!!!!!!!

Mathematics
1 answer:
Norma-Jean [14]3 years ago
3 0

Answer:

Look at the lightest loaf of bread. It weighs 22 1/3 oz. The heavist loaf weighs 24 1/2. Subtract 24 1/2 and 22 1/3. Then, if the answer to that is 1 1/2 ounces then you agree. If it is not, then disagree. Then, add up all of the weights of the bread and find the answer.

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Select the ordered pair that is the solution of this equation: -7x – 4y = 6
Olegator [25]
Its just a matter of subbing

-7x - 4y = 6....subbing in (-2,2)...x = -2 and y = 2
-7(-2) - 4(2) = 6
14 - 8 = 6
6 = 6 (correct)

so ur solution is (-2,2)
4 0
3 years ago
What's the Answer? Provide steps please​
dalvyx [7]

Answer:

0.24930286...

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
f a random sample of 300 adults is taken from the state of Colorado, where the rate of obesity is 19.8%, can we use the Normal a
Troyanec [42]

Answer:

Probability of at least 50 obese individuals in our sample is 0.92364 .

Step-by-step explanation:

We are given that a random sample of 300 adults is taken from the state of Colorado, where the rate of obesity is 19.8% .

Let X = Number of obese individuals

Firstly, X ~ Binom(n=300,p=0.198)

For approximating binomial distribution into normal distribution, firstly we have to calculate \mu and \sigma^{2} .

Mean of Normal distribution, \mu = n * p = 300 * 0.198 = 59.4

Variance of Normal distribution,\sigma^{2} = n * p * (1-p) = 300 *0.198 *0.802 = 47.64

So, now X ~ N(\mu = 59.4 , \sigma^{2} = 47.64)

The standard normal z score distribution is given by;

                     Z = \frac{X-\mu}{\sigma} ~ N(0,1)

So, probability of at least 50 obese individuals in our sample = P(X >= 50)

  P(X >= 50) = P(X > 49.5)  {using continuity correction}

  P(X > 49.5) = P( \frac{X-\mu}{\sigma} > \frac{49.5 - 59.4}{6.9} ) = P(Z > -1.43) = P(Z < 1.43) = 0.92364

Therefore, required probability is 0.92364 .

8 0
3 years ago
60<br> What is the sum of the series E3n?
wariber [46]

Answer:

B, 2,010

Hope this helps have a nice day/night :)

6 0
2 years ago
Read 2 more answers
The mean consumption of bottled water by a person in the United States is 28.5 gallons per year. You believe that a person consu
Over [174]

Answer:

t=\frac{27.8-28.5}{\frac{4.1}{\sqrt{100}}}=-1.707    

p_v =P(t_{99}

If we compare the p value with a significance level for example \alpha=0.1 we see that p_v so we can conclude that we reject the null hypothesis, so there is not enough evidence to conclude that the mean for the consumption is less than 28.5 gallons at 0.1 of significance, so we can reject the claim that person consume more than 28.5 gallons.

Step-by-step explanation:

Data given and notation    

\bar X=27.8 represent the mean for the account balances of a credit company

s=4.1 represent the population standard deviation for the sample    

n=1000 sample size    

\mu_o =28.5 represent the value that we want to test  

\alpha=0.1 represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)    

p_v represent the p value for the test (variable of interest)

State the null and alternative hypotheses.    

We need to conduct a hypothesis in order to determine if the mean for the person consume is more than 28.5 gallons, the system of hypothesis would be:    

Null hypothesis:\mu \geq 28.5    

Alternative hypothesis:\mu < 28.5    

We don't know the population deviation, so for this case we can use the t test to compare the actual mean to the reference value, and the statistic is given by:    

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)    

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic    

We can replace in formula (1) the info given like this:    

t=\frac{27.8-28.5}{\frac{4.1}{\sqrt{100}}}=-1.707    

Calculate the P-value    

First we need to calculate the degrees of freedom given by:

df=n-1=100-1=99

Since is a one-side lower test the p value would be:    

p_v =P(t_{99}

In Excel we can use the following formula to find the p value "=T.DIST(-1.707,99)"  

Conclusion    

If we compare the p value with a significance level for example \alpha=0.1 we see that p_v so we can conclude that we reject the null hypothesis, so there is not enough evidence to conclude that the mean for the consumption is less than 28.5 gallons at 0.1 of significance, so we can reject the claim that person consume more than 28.5 gallons.

5 0
3 years ago
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