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earnstyle [38]
2 years ago
11

What is the volume of the complex shape?

Mathematics
2 answers:
Oksana_A [137]2 years ago
8 0

Answer:

100000000000000000000

Hoochie [10]2 years ago
3 0

Answer:

<h3>72 cm^3</h3>

Step-by-step explanation:

Area = 12 cm^2

Length = 6 cm

Volume = 12 * 6 = 72 cm^3

<h2>MARK ME AS BRAINLIEST OR WHATEVER JUST GIVE ME THE POINTS </h2>
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Answer:

5y345

Step-by-step explanation:

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6 0
2 years ago
Find the volume of each ball. use the formula. where v is the volume and r is the radius. record the volume in table A of your s
pochemuha

Answer:

The volume of tennis ball = 38.808 cm^{3}.

                          Volume of golf ball = 33.523 cm^{3}.


Step-by-step explanation:

Given: The radius of the tennis ball is 2.1cm and the radius of thr golf ball is 2.0cm. the formula is V=4πr(to the 3rd power) /3 .

To find: Volume of tennis ball and golf ball .

Formula used: Volume = \frac{4 π r^{3} }{3} .

 pi(π) = \frac{22}{7} .

Explanation : We are given that

                     Radius of the tennis ball = 2.1 cm

                    radius  of the golf ball =2.0 cm.

We need to find the volume of each ball

So , plugging the given values of radius in above formula

Volume of the tennis =\frac{4*22(2.1)^{3} }{3*7}

On simplification we get, volume of tennis ball = 38.808 cm^{3}

Volume of the golf ball=\frac{4*22(2.0)^{3} }{3*7}

On simplification we get, volume of golf ball = 33.523 cm^{3}

Therefore , The volume of tennis ball = 38.808 cm^{3}.

                          Volume of golf ball = 33.523 cm^{3}.


7 0
3 years ago
Read 2 more answers
Which statement about the equation is true? x + 2 = x + 4
ryzh [129]
No solution because you can’t even out both sides
6 0
3 years ago
Read 2 more answers
How do I solve question 2?
sdas [7]

you multiply the number of years

6 0
3 years ago
Suppose a regular n-gon is inscribed in a circle of radius r. Diagrams are shown for n=6, n=8, and n = 12. n = 6 n=8 n = 12 a a
m_a_m_a [10]

Answer:If an N-gon (polygon with N sides) has perimeter P, then each of the  

N sides has length P/N.  If we connect two adjacent vertices to the  

center, the angle between these two lines is 360/N degrees, or 2*pi/N  

radians.  (Do you understand radian measure well enough to follow me  

this far?)

The two lines I just drew, plus the side of the polygon between them,  

form an isosceles triangle.  Adding the altitude of the isosceles  

triangle makes two right triangles, and we can use one of them to  

derive the equation

 sin(theta/2) =  s/(2R)

where theta is the apex angle (which I said is 2*pi/N radians), R is  

the length of the lines to the center (the radius of the circumscribed  

circle), and s is the length of the side (which I said is P/N).

Putting those values into the equation, we have

 sin(pi/N) = P/(2NR)

so that

 P = 2NR sin(pi/N)

gives the perimeter of the N-gon with circumradius R.

Can we see a connection between this formula and the perimeter of a  

circle?  The perimeter of the circumcircle is 2*pi*R.  As we increase  

N, the perimeter of the polygon should get closer and closer to this  

value.  Comparing the two, we see

 2NR*sin(pi/N) approaches 2*pi*R

 N*sin(pi/N)   approaches pi

You can check this out with a calculator, using big numbers for N such  

as your teacher's N=1000.  If you calculate the sine of an angle in  

degrees rather than radians, the formula will look like

 N*sin(180/N) --> pi

Step-by-step explanation:

6 0
3 years ago
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