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Kipish [7]
3 years ago
8

Solve the equation 9x^2-29x-28=0 give your answer to decimal places when appropriate

Mathematics
1 answer:
Hatshy [7]3 years ago
6 0

Answer:

<em>The solution of the given equation is x = 4</em>

Step-by-step explanation:

Given equation 9 x² - 29 x - 28 =0

 The Factors of  252 is  3 6 × 7

         now          9 x² - 36 x + 7 x - 28 =0

taking common terms , we get

                         9 x ( x -4) + 7 ( x - 4) = 0

                         (9 x + 7) (x - 4) = 0

                         9 x + 7 = 0 and x - 4 = 0

            x = \frac{-7}{9} = - 0.7778     and  x =4

x = \frac{-7}{9} = - 0.7778 is not satisfied of the given equation

<em>The solution of the given equation is x = 4</em>

                     

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Kinda ned some help how do i solve this problem
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3 years ago
What is the Evaluate the expression.<br> 15.6−(−13.7−8.5)
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Solve the following equation x²=64​
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Answer:

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Step-by-step explanation:

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Answer:

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3 years ago
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How is the sum expressed in sigma notation?<br><br> 11 + 17 + 23 + 29 + 35 + 41
Ann [662]
<h3>The sum expressed in sigma notation is:</h3>

11+17+23+29+35+41=\sum\limits_{i=1}^{6}5+6i

<u><em>Solution:</em></u>

Given that,

11 + 17 + 23 + 29 + 35 + 41

We have to express the sum in sigma notation

Analyse the series

5 + 6(1) = 11

5 + 6(2) = 17

5 + 6(3) = 5 + 18 = 23

5 + 6(4) = 5 + 24 = 29

5 + 6(5) = 5 + 30 = 35

5 + 6(6) = 5 + 36 = 41

<em><u>Thus the series goes on like this:</u></em>

5 + 6(n) , where n = 1 to 6

<em><u>This can be expressed in sigma notation as:</u></em>

11+17+23+29+35+41=\sum\limits_{n=1}^{6}5+6n

<em><u>We can expand the sigma notation and verify the results</u></em>

\sum\limits_{i=1}^{6}5+6i=(5+6(1))+(5+6(2))+(5+6(3))+(5+6(4))+(5+6(5))+(5+6(6))\\\\\\\sum\limits_{i=1}^{6}5+6i=(5+6)+(5+12)+(5+18)+(5+24)+(5+30)+(5+36)\\\\\\\sum\limits_{i=1}^{6}5+6i=11+17+23+29+35+41

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