Rate of change is Rise over run=3/36=1/12 inches
<em>The question doesn't ask anything in particular, I will show the set of inequalities defined in the problem.</em>
Answer:
<em>System of inequalities:</em>
Step-by-step explanation:
<u>Inequalities
</u>
The express relations between expressions with a sign other than the equal sign. Common relationals are 'less than', 'greater than', 'not equal to', and many others.
The gardening club at school has 300 square feet of planting beds to plant cucumber and tomato. Each cucumber plant requires 6 square feet of growing space and each tomato plant requires 4 square feet of growing space. We know the total area cannot exceed 300 square feet, so
Being c and t the number of cucumber and tomato plants respectively.
We also know the students want to plant some of each type of plant and have at least 60 plants. This lead us to more conditions
<em>Note: The set of inequalities shown is not enough to uniquely solve the problem. We need something to maximize or minimize to optimize c and t</em>
Explanation:
Marginal distribution: This distribution gives the probability for each possible value of the Random variable ignoring other random variables. Basically, the values of other variables is not considered in the marginal distribution, they can be any value possible. For example, if you have two variables X and Y, the probability of X being equal to a value, lets say, 4, contemplates every possible scenario where X is equal to 4, independently of the value Y has taken. If you want the probability of a dice being a multiple of 3, you are interested that the dice is either 3 or 6, but you dont care if the dice is even or odd.
Conditional distribution: This distribution contrasts from the previous one in the sense that we are restricting the universe of events to specific condition for other variable, making a modification of our marginal results. If we know that throwing a dice will give us a result higher than 2, then to in order to calculate the probability of the dice being a multiple of 3 using that condition, we have two favourable cases (3 and 6) from 4 total possible results (3,4,5 and 6) discarding the impossible values (1 and 2) from this universe since they dont match the condition given (note that the restrictions given can also reduce the total of favourable cases).
The joint distribution calculates the probabilities for two different events (related to two different random variables) occuring simultaneously. If we want to calculate the joint probability of a dice being multiple of 3 and greater than 2 at the same time, our possible cases in this case are 3 and 6 from 6 possible results. We are not discarding 1 or 2 as possible results because we are not assuming, that the dice is greater than 2, that is another condition that we should met in the combination of events.
Answer:
x = 0
Step-by-step explanation:
Take out common factor
The factor inside the parenthesis cannot be factored
Since there is a common factor that we pulled out of the original equation,
set that x equal to zero and solve
: Therefore x = 0
Answer:
Step-by-step explanation:
