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ruslelena [56]
2 years ago
14

What is the solution of 5/6 x 4/9.

Mathematics
2 answers:
Sphinxa [80]2 years ago
8 0

<em>The</em><em> </em><em>answer</em><em> </em><em>is</em><em> </em><em>1</em><em>0</em><em>/</em><em>2</em><em>7</em>

<em>pl</em><em>ease</em><em> see</em><em> the</em><em> attached</em><em> picture</em><em> for</em><em> full</em><em> solution</em>

<em>h</em><em>ope</em><em> it</em><em> will</em><em> </em><em>helps</em>

<em>G</em><em>ood</em><em> luck</em><em> on</em><em> your</em><em> assignment</em>

oksano4ka [1.4K]2 years ago
8 0

Answer:

10/27  

Step-by-step explanation:

5/6 x 4/9=5/3 x 2/9=10/27  

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3 years ago
Solve the equation 1/6(x - 5) = 1/2(x + 6)
Semmy [17]

Answer:

-23/2

Step-by-step explanation:

x-5=3(x+6)

x-3x=18+5

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5 0
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Answer and show proof for brainliest
kodGreya [7K]

Answer:

12

Step-by-step explanation:

Add each number given = 132

132 / 6 (amount of given numbers)

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2 years ago
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If total liabilities decreased by $60,000 and stockholders' equity increased by $20,000 during a period of time, then total asse
Lena [83]

Answer:

$40,000 decrease

Step-by-step explanation:

Change in total assets = Total Liabilities Decreased- StockHolders' equity increased

Change in total assets = 60000 - 20000

Change in total assets = $40,000 decrease

So, If total liabilities decreased by $60,000 and stockholders' equity increased by $20,000 during a period of time,<u><em>then the change in total assets will consist of a </em></u><u><em>decrease of $40,000 </em></u>

3 0
3 years ago
Is the point (16,20) on line ℓ?<br><br><br>​
kicyunya [14]

Answer:

YES

Step-by-step explanation:

Find the equation of the line written as, y = kx. The graph shows a proportional relationship between y and x.

Constant of proportionality/unit rate/slope (k) = rise/run = ⁵/4.

Substitute ⁵/4 in y = kx

We would have:

y = ⁵/4x.

Using the equation of the line, we can know if a given point is on the line by plugging the value of x and y coordinates of the point into the equation. If it makes the equation true, then it is a point on the line. If it doesn't make the equation true, then it isn't a point on the line.

Let's plug in (16, 20) into y = ⁵/4x.

Thus substitute x = 16 and y = 20, we have:

[tex] 20 = \frac{5}{4}(16) [/trex]

[tex] 20 = (5)(4) [/trex]

[tex] 20 = 20 [/trex]

It makes the equation true. Therefore, the point, (16, 20) is a point on line l.

7 0
2 years ago
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