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Sliva [168]
3 years ago
13

What is the equation of the line?

Mathematics
1 answer:
kherson [118]3 years ago
6 0

That's a vertical line, no slope, so no y=something.  

Answer: x = -9

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What is the mean absolute deviation for 2,9, 1, 7, 8, 9
Phantasy [73]

Answer:

3 :)

Step-by-step explanation:

3 0
3 years ago
Find the slope (8,-5) (8,10)​
andreev551 [17]

Finding the slope using two points:

The formula for slope is

\frac{y_{2}-y_{1}}{x_{2}-x_{1}}

In this case...

y_{2} =10\\y_{1} =-5\\x_{2} =8\\x_{1} =8

^^^Plug these numbers into the formula for slope...

\frac{10-(-5)}{8-8

\frac{15}{0}

Your slope is undefined. This means that you line is vertical

Hope this helped!

~Just a girl in love with Shawn Mendes

3 0
3 years ago
A particular number was divided by 6 qnd then 5 was taken away from the quotient. Finally, the difference was mutiplird by 2. Gi
Nitella [24]
N is the number
divided by 6 then n/6
5 was taken away so (n/6)-5
the result is multiplied by 2 so 2((n/6)-5)
result is -12

-12=2((n/6)-5)
divide both sides by 2
-6=(n/6)-5
add 5
-1=n/6
times 6
-6=n
da number was -6
6 0
4 years ago
Points (−6, 3) and (−6, −3) on the coordinate grid below show the positions of two dogs at a park: A coordinate plane is shown.
Nostrana [21]

Question:

Points (−6, 3) and (−6, −3) on the coordinate grid below show the positions of two dogs at a park.There is a point at (−6, 3) labeled Dog 1. There is a point at (−6, −3) labeled Dog 2.

Which statement best describes the relationship between the positions of the two players?

A.Dog 1's position is Dog 2's position reflected across the y-axis; only the signs of the y-coordinates of Dog 1 and Dog 2 are different.

B.Dog 1's position is Dog 2's position reflected across the x-axis; only the signs of the y-coordinates of Dog 1 and Dog 2 are different.

C.Dog 1's position is Dog 2's position reflected across the x-axis; only the signs of the x-coordinates of Dog 1 and Dog 2 are different.

D. Dog 1's position is Dog 2's position reflected across the y-axis; only the signs of the x-coordinates of Dog 1 and Dog 2 are different.

Answer:

Option B: Dog 1's position is Dog 2's position reflected across the x-axis; only the signs of the y-coordinates of Dog 1 and Dog 2 are different.

Explanation:

The position of the Dog 1 is (−6, 3).

The position of the Dog 2 is (−6, -3).

From the graph, we can see that the image of Dog 1 is reflected over x-axis. Because to reflect an image over x-axis, the signs of y-coordinate must be changed.

Hence, Option B is correct.

Thus, Dog 1's position is Dog 2's position reflected across the x-axis; only the signs of the y-coordinates of Dog 1 and Dog 2 are different.

7 0
3 years ago
5. If W(-10, 4), X(-3,-1), and Y(-5, 11) classify AWXY by its sides. Show all work to justify your
Ierofanga [76]

Answer:

  an isosceles right triangle

Step-by-step explanation:

The square of the length of a side can be found from the distance formula:

  d^2 = (x2-x1)^2 +(y2-y1)^2

The square of the length of WX is ...

  WX^2 = (-3-(-10))^2 +(-1-4)^2 = 49+25 = 74

The square of the length of XY is ...

  XY^2 = (-5-(-3))^2 +(11-(-1))^2 = 4 +144 = 148

The square of the length of YW is ...

  YW^2 = (-10-(-5))^2 +(4 -11)^2 = 25 +49 = 74

The sum of the squares of the short sides is equal to the square of the long side, so this is a right triangle. The squares of the short sides are equal, so this is an isosceles right triangle.

3 0
3 years ago
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