Answer:
The correct answer is C) There is a larger variety of MHC proteins that can be expressed on the cell surfaces of their immune cells, providing a wider opportunity to recognize and attack pathogens.
Explanation:
Answer:
The continents were once connected as one landmass.
Explanation:
This did happen it's called Pangea. There were similar fossil records in different continents.
Correct option C) Hydrophilic portions of the lipids are in the interior of the membrane.
Lipids and proteins free to move laterally in membranes because both are inserted into a fluid lipid bi-layer and they are able to diffuse laterally through the membrane.
Lipid Composition of Cell Membranes is a important property of lipid bilayers which is behave as two-dimensional fluids where individual molecules are rotate and move freely in lateral directions
Membrane proteins and phospholipids both are unable to move back and forth between the inner and outer leaflets of the membrane at an appreciable rate. Phospholipids in the lipid bilayer can either move rotationally, laterally in one bilayer, or undergo transverse movement between bilayers.
To learn more about Cell Membranes here
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Answer:
(a) 0.16
(b) 1
Explanation:
Let Probability that ticks in the Midwest carried Lyme disease, P(L) = 0.16
Probability that ticks in the Midwest carried HGE disease, P(H) = 0.10
Probability that ticks in the Midwest carried either Lyme disease or HGE disease, P(
) = 0.10
(a) Probability that a tick carries both Lyme disease (L) and HE (H) is given by
P(L 
H);
As we know that P(A 
B) = P(A) + P(B) - P(A B)
So, in our question;
P(L H) = P(L) + P(H) - P(L H)
0.10 = 0.16 + 0.10 - P(L H)
P(L H) = 0.16 + 0.10 - 0.10 = 0.16
Therefore, the probability that a tick carries both Lyme disease (L) and HE (H) is 0.16 or 16% .
(b) <em>Conditional Probability P(A/B) is given by</em> = 
So, the conditional probability that a tick has HE given that it has Lyme disease is given by = P(H/L)
P(H/L) = 
= 
= 1 .
