Answer:
2042.6$
Step-by-step explanation:
12853(5/100)+1400
The area of circle mowed is 6644.24 square feet.
Step-by-step explanation:
Given,
Radius of circle = 46 feet
Area of circle is given by πr².
Area of circle = 
Area of circle = 
Area of circle = 3.14 * 2116
Area of circle = 6644.24 square feet
The area of circle mowed is 6644.24 square feet.
The balloon has a volume
dependent on its radius
:

Differentiating with respect to time
gives

If the volume is increasing at a rate of 10 cubic m/s, then at the moment the radius is 3 m, it is increasing at a rate of

The surface area of the balloon is

and differentiating gives

so that at the moment the radius is 3 m, its area is increasing at a rate of
