Answer:
I'm not sure for my answer but is B
I'm gonna put the steps
Step-by-step explanation:
x2−4x−12as(x+p)(x+q)
=−12apqs−12apsx−12aqsx−12asx2+x2−4x
Answer:
a) 72.25sec
b) 6.25secs
c) after 10.5secs and 2 secs
Step-by-step explanation:
Given the height reached by the rocket expressed as;
s(t)= -4t^2 + 50t - 84
At maximum height, the velocity of the rocket is zero i.e ds/dt = 0
ds/dt = -8t + 50
0 = -8t + 50
8t = 50
t = 50/8
t = 6.25secs
Hence it will reach the maximum height after 6.25secs
To get the maximum height, you will substitute t - 6.25s into the given expression
s(t)= -4t^2 + 50t - 84
s(6.25) = -4(6.25)^2 + 50(6.25) - 84
s(6.25) = -156.25 + 312.5 - 84
s(6.25) = 72.25feet
Hence the maximum height reached by the rocket is 72.25feet
The rocket will reach the ground when s(t) = 0
Substitute into the expression
s(t)= -4t^2 + 50t - 84
0 = -4t^2 + 50t - 84
4t^2 - 50t + 84 = 0
2t^2 - 25t + 42 = 0
2t^2 - 4t - 21t + 42 = 0
2t(t-2)-21(t-2) = 0
(2t - 21) (t - 2) = 0
2t - 21 = 0 and t - 2 = 0
2t = 21 and t = 2
t = 10.5 and 2
Hence the time the rocket will reach the ground are after 10.5secs and 2 secs
answer is x is less than or equal to -13
hope this helps:-)
Answer:Jeff's restaurant
Step-by-step explanation:
I'm pretty sure its right
Answer:
To get the x-intercepts of the function, f(x) = 4x2 – 24x + 20
It has to be equated to zero and the values of x are the x-intercepts. So,
4x2 – 24x + 20 = 0
The resulting equation is a quadratic equation which can be solved by different methods. The solution is
x = 5, 1
The average therefore is:
(1+5/)2 = 3
