Solve this system of equation using any method. 4x-y=5 and 3x+y=16
2 answers:
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*the diagram of the Russian stringed instrument is attached below.
Answer/Step-by-step explanation:
To show that the traingular parts of the two balalaikas instruments are congruent, substitute x = 6, to find the missing measurements that is given in both ∆s.
Parts of the first ∆:
WY = (2x - 2) in = 2(6) - 2 = 12 - 2 = 10 in
m<Y = 9x = 9(6) = 54°.
XY = 12 in
Parts of the second ∆:
m<F = 72°
HG = (x + 6) in = 6 + 6 = 12 in
HF = 10 in
m<G = 54°
m<H = 180 - (72° + 54°)
m<H = 180 - 126
m<H = 54°
From the information we have, let's match the parts that are congruent to each other in both ∆s:
WY ≅ FH (both are 10 in)
XY ≅ GH (both are 12 in)
<Y ≅ <G (both are 54°)
Thus, since two sides (WY and XY) and an included angle (<Y) of ∆WXY is congruent to two corresponding sides (FH and GH) and an included angle (<G) in ∆FGH, therefore, ∆WXY ≅ ∆FGH by the Side-Angle-Side (SAS) Congruence Theorem.
This is enough proof to show that the triangular parts of the two balalaikas are congruent for x = 6.
Using the binomial distribution, it is found that there is a 0.25 = 25% probability he will land on A on the first spin and A and the second.
For each spin, there are only two possible outcomes, either it lands on Sector A, or it does not. The results of each spin are independent, hence, the binomial distribution is used to solve this question.
<h3>What is the binomial distribution formula?</h3>The formula is:
The parameters are:
- x is the number of successes.
- n is the number of trials.
- p is the probability of a success on a single trial.
In this problem, we have that:
- The sectors are equal, which means that it is equally as likely to land on each, hence
.
- Saul will spin the wheel twice, hence
.
The probability that both land on A is P(X = 2), hence:
0.25 = 25% probability he will land on A on the first spin and A and the second.
You can learn more about the binomial distribution at brainly.com/question/24863377