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lyudmila [28]
3 years ago
7

Juanita ran 8.3 miles in Week 1 and 12.09 miles in Week 2. She used the subtraction below to determine how much farther she ran

in Week 2 than in Week 1.
12.09 minus 8.30 = 4.79. All decimals are aligned. The 0 in 12.09 is crossed out and a 1 is above it. The 2 is crossed out in 12.09 and a 1 is above it.

Which error did Juanita make?
She subtracted instead of added.
She aligned the decimal points incorrectly.
She did not regroup correctly when subtracting.
She made a computational error when subtracting.

Mathematics
2 answers:
AfilCa [17]3 years ago
7 0

Step-by-step explanation:

12.09 - 8.30 = 3.79

The reason why her answer was wrong is because when the '2' gets slashed into a '1' during carry over, it would have been 11 - 8 = 3 instead of a 4. (the 1st column)

The error that Juanita made is that she made a computational error when subtracting.

Llana [10]3 years ago
5 0

Answer:

  • She made a computational error when subtracting.

Step-by-step explanation:

<u>She subtracted instead of added. </u>

  • No, she needed to subtract to find the difference.

<u>She aligned the decimal points incorrectly. </u>

  • No, she did it right.

<u>She did not regroup correctly when subtracting. </u>

  • No, she regrouped correctly.

<u>She made a computational error when subtracting.</u>

  • Yes. She made an error at last step, instead of subtracting 8 from 11 she subtracted 8 from 12 and got the first digit wrong (4 instead of 3).
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What are the coordinates of the orthocenter of △JKL with vertices at J(−4, −1) , K(−4, 8) , and L(2, 8) ?
Sati [7]

<u>Answer-</u>

<em>The coordinates of the orthocenter of △JKL is (-4, 8)</em>

<u>Solution-</u>

The orthocenter is the point where all three altitudes of the triangle intersect. An altitude is a line which passes through a vertex of the triangle and is perpendicular to the opposite side.

For a right angle triangle, the vertex at the right angle is the orthocentre of the triangle.

Here we are given the three vertices of the triangle are  J(-4,-1), K(-4,8) and L(2,8)

If the triangle JKL satisfies Pythagoras Theorem, then triangle JKL will be a right angle triangle.

Applying distance formula we get,

JK^2= (-4+4)^2+ (8+1)^2=0+81=81\\\\KL^2= (-4-2)^2+ (8-8)^2=36+0=36\\\\JL^2= (-4-2)^2+(8+1)^2=36+81=117

As,

\Rightarrow 117=81+36

\Rightarrow JL^2=JK^2+KL^2

\Rightarrow \text{JKL is a right angle triangle}

\Rightarrow \angle K=90^{\circ}

Therefore, the vertex at K (-4, 8) is the orthocentre.

3 0
3 years ago
A taxi fare has a fixed charge of $1.75 and an additional charge $0.45 per mile. A fare for m miles is $13.90. Which equation co
Anestetic [448]

Answer:

B) 1.75 + 0.45m = 13.90

Step-by-step explanation:

To calculate the Taxi fare, we need to sum the fixed charge and the additional charge. Fixed charge ever is $1.75. The additional charge changes with the miles traveled (one mile costs $0.45, two miles $0.90, and so on), so we need multiply the charge ($0.45) by the miles m traveled.  

1.75 + 0.45 m

The problem says that the fare was equals to $13.90 so the final equation is

1.75 + 0.45m = 13.90

6 0
3 years ago
Find the percent of the number. explain your method 120%of 75
cupoosta [38]
I would use is over of equals percent over 100 is woudl be 120% and of would be 75 then you would put x over 75
5 0
3 years ago
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The table shows data gathered by an environmental agency about the decreasing depth of a lake during the first few months of a d
Elanso [62]
(0,346)(2,344.8)
slope = (344.8 - 346) / (2 - 0) = -1.2 / 2 = -0.6

y = mx + b
slope(m) = -0.6
(0,346)...x = 0 and y = 346
now we sub and find b, the y int
346 = -0.6(0) + b
346 = b
so ur equation is : y = -0.6x + 346....with x being the number of weeks

after 4 weeks...
y = -0.6(4) + 346
y = - 2.4 + 346
y = 343.6 <==== after 4 weeks

after 9 weeks..
y = -0.6(9) + 346
y = -5.4 + 346
y = 340.6 <=== after 9 weeks

7 0
3 years ago
What is three equivalent ratios for 9/2?
andreyandreev [35.5K]
\frac{18}{4}; \frac{27}{6}; \frac{36}{8}
6 0
4 years ago
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