Answer:
Population next year = 1.075p
Step-by-step explanation:
The current population can be represented by 1 p the increase in the population number by next year is 7.5% p or 7.5/100 p that equals to 0.075p. The expression that represents the expected population by next year is:
Population next year = This year population + expected growth
Population next year = 1p + 0.075p = 1.075p
So what this is is
many words
assuming year 0 is 2017
so compound first thing till 2020, take out 30000
the remaining is copmpounded til 2022, take out 50000
remaining is compounded for 1 more year and that is equal to 80000
so from 2017 to 2020, that is 5 years
from 2020 to 2022 is 2 years
from 2022 to 2023 is 1 year
work backwards
A=P(r+1)^t
last one
A=80000
P=?
r=0.08
t=1 year
80000=P(1.08)^1
divide both sides by 1.08
I would leave in fraction
20000000/27=P
now that is the remaining after paying 50000, after 2 years of compounding
so
50000+(2000000/27)=P(1.08)^2
solve using math
about
106374=P
now reverse back
5 years
paid 30000
30000+106374=P(1.08)^5
solve using math
92813.526=P
round
$92813.53
put $92813.53 in the fund
Answer:
As law of sin:
CD/sinE = DE/sinC
Then
12/sin83 = 5/sinC
Then
sinC = 5*sin83/12 = 0.413
Then
C = arcsin(0.413) = ~24.4 deg
Then
D = 180-C-E = 180-83-24.4 = ~72.6
Hope this help, bro!
If you follow PEMDAS
P-parentheses
E-exponent
M-multiplication
D-divide
a-addition
s-subtraction
then you should look in the parentheses and multiplying 3x should be your first step IF you know x
hope this helps :)
Answer:
Step-by-step explanation:
1 n=0
1 1 n=1
1 2 1 n=2
1 3 3 1 n=3
1 4 6 4 1 n=4
1 5 10 10 5 1 n=5
1 6 15 20 15 6 1 n=6
This is where n is the exponent in
.
Now we want to expand:
or we we can rewrite as 
.
Let's replace 
with 
and 
with 
in the expansion:
Let's simplify a bit:
