Answer:
Step-by-step explanation:
for this problem u need the unit circle.
In the unit circle there is a point with -1/2 as the x value that is at 240 degrees.
then you convert 240 degrees to radians --> 240 X pi/180 = 4.189
the unit circle is below, you needa remember for the test
Good luck on your EOC, i'm doing it too
The question is incomplete, the complete question is here
Find the measures of the angles of an isosceles triangle whose equal sides measure 8 and whose altitude drawn to the base measures 4
Answer:
The measures of the angles of the isosceles triangle are 30°, 30° and 120°
Step-by-step explanation:
In a triangle whose sides a, b, c and angles A, B and C, where a is opposite to ∠A, b is opposite to ∠B, and c is opposite to ∠C, the given is
The height from ∠B to side b is 4 units
That means the length of the height is half the length of each equal sides, then there is a right triangle its hypotenuse is 8 and the side opposite to the base angle is 4, so we can find the measure of the base angle by using the rule sin(base angle) =
∵ The base angles are ∠A and ∠C
∵ a = c = 8
∵ The altitude to b is 4
∵
- By using
∴ m∠A =
∴ m∠A = 30°
∵ m∠A = m∠C
∴ m∠C = 30°
Use the rule of the sum of the measures of the interior angle of a Δ is 180° to find m∠B
∵ m∠A + m∠C + m∠B = 180
∵ m∠A = m∠C = 30°
∴ 30° + 30° + m∠B = 180°
∴ 60 + m∠B = 180
- Subtract 60 from both sides
∴ m∠B = 120°
The measures of the angles of the isosceles triangle are 30°, 30° and 120°