I don't really understand this question do u have a pic
Solving a system of equations we will see that we need to use <u>40 liters of the 80% acid solution</u>, and the other <u>20 liters are of the 35% acid solution</u>.
<h3>
How many liters of each solution do we need to use?</h3>
First, we need to define the variables:
- x = liters of the 35% acid used.
- y = liters of the 80% acid used.
We know that we want to produce 60 liters of 65% acid, then we have the system of equations:
x + y = 60
x*0.35 + y*0.80 = 60*0.65
(in the second equation we wrote the percentages in decimal form).
To solve this we need to isolate one of the variables in one equation and then replace it in other one, isolating x we get:
x = 60 - y
Replacing that in the other equation:
(60 - y)*0.35 + y*0.80 = 60*0.65
y*(0.80 - 0.35) = 60*(0.65 - 0.35)
y*0.45 = 60*0.30
y = 60*0.30/0.45 = 40
So we need to use <u>40 liters of the 80% acid solution</u>, and the other <u>20 liters are of the 35% acid solution</u>.
If you want to learn more about systems of equations:
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The most appropriate choice for simple interest will be given by- Balance of Jose after 1 year is $1050
What is simple interest?
Simple interest is the interest applied on the principal value after charging some certain percentage of rate for some certain amount of time.
If the principal value is p, rate is r % per annum and time is t years
Simple interest is calculated as
SI = p ₓ r ₓ t / 100
Here,
Principal for Jose = $1000
Rate = 5%
Time = 1 year
Simple interest = 1000x5x1/100
= $50
Amount = $(1000+50)
= $1050
Balance of Jose after 1 year is $1050
To learn more about simple interest, refer to the link:
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Answer:
27
Step-by-step explanation:
if 5n is equal to 135 the divide both sides with 5 and you will see 1n is equal to 27
