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3 years ago

Can you help me simplify it?

Mathematics

1 answer:

adelina 88 [10]3 years ago

8 0

The answer to your question is -2xy+5x^2+4y-10x. Hope this helps and let me know if it was right.

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Evaluate the following expression when n=6. -6|n+3|

julia-pushkina [17]

I believe the answer is -33

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3 years ago

It takes 1 1/3 hours to set up 1/3 of an hour to run and 2/3 of an hour to verify the results. How many hours will it take to co

liraira [26]

Answer: It will take $\frac{7}{3}$ of an hour to complete the test.

Step-by-step explanation:

We need to convert the mixed number $1\ \frac{1}{3}$ to an improper fraction:

$1\ \frac{1}{3}=\frac{(1*3)+1}{3}= \frac{4}{3}$

Now, we need to make the following add the fractions in order to calculate how many hours will it take to complete the test. Then, we get:

$\frac{4}{3}+\frac{1}{3}+\frac{2}{3}=\frac{4+1+2}{3}=\frac{7}{3}$

Therefore, it will take $\frac{7}{3}$ of an hour to complete the test.

5 0

3 years ago

Jim and his dad are building a rectangular flower bed. They have a total of 35 feet of landscaping timber to use, and they want

Mama L [17]

The perimeter is 35. If we were to change the width, which is one of the dimensions of the flower bed, The perimeter will change. This means that perimeter will no longer be 35. So in order to keep the perimeter as it is, if we change one dimension, we must also change the other. Let's solve for the length, using the formula to see how much the length changes from. p = 2l + 2w 35 = 2l + 2(15) 35 = 2l + 30 5 = 2l 2.5 = l We must increase the length from 2.5 feet. This is because decreasing one dimension will decrease the perimeter. But if we increase the other dimension as well, it will restore the perimeter to where is was initially.

4 0

3 years ago

Read 2 more answers

Find the second derivative, do not have to simplify

zlopas [31]

$f(x)=\sec(\pi x)=\dfrac{1}{\cos(\pi x)}=[\cos(\pi x)]^{-1}\\\\\text{use}\\\\(a^n)'=na^{n-1}\\\\(\cos x)'=-\sin x\\\\f'(g(x))=f'(g(x))\cdot g'(x)$

$f'(x)=\left\{[\cos(\pi x)]^{-1}\right\}'=-[\cos(\pi x)]^{-2}\cdot[-\sin(\pi x)]\cdot\pi\\\\=\dfrac{\pi\sin(\pi x)}{[\cos(\pi x)]^2}=\pi\dfrac{\sin(\pi x)}{\cos(\pi x)}\cdot\dfrac{1}{\cos(\pi x)}\\\\=\pi\tan(\pi x)\sec(\pi x)$

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3 years ago

Pls answer me no links or ill report

I am Lyosha [343]

Answer:

Step-by-step explanation:

B, C and D are all equations.

A is the only one that is not.

The answer is A.

7 0

3 years ago