Hello again!
It looks like you need a lot of help today. I'm glad I am able to help you!
h(x) = x³ - 2x² - 3x
The question you need to ask yourself is "How do you find the zeros of a function.
Answer: To find the zeros of a function, just set the function equal to zero then solve for x
x³ - 2x² - 3x = 0
Factor the left sides
x(x + 1)(x - 3) = 0
Now we can set factors equal to 0
x = 0 or x + 1 = 0 or x - 3 = 0
x = 0 or x = 0 - 1 or x = 0 + 3
x = 0 or x = -1 or x = 3
Thus,
The zeros of the function are: x = 0 or x = -1 or x = 3
As always, I am glad to help students like you!
Answer:
No, because the number of trials is not fixed.
Step-by-step explanation:
a. pe. x
9x-7=-7
+7 +7
___________
9x= 0
_ _
9 9
x=0
Answer:
Is that all to the problem?
Step-by-step explanation:
Answer:
Rs 8500
Step-by-step explanation:
For a cost price of c, the marked price is ...
marked = c +25%·c = 1.25c
After the 15% discount, the sale price will be ...
s = marked -15%·marked = 0.85·marked = (0.85)(1.25c) = 1.0625c
The profit will be the difference between the sale price s and the cost c:
p = s -c
500 = (1.0625c) -c = 0.0625c
Then the cost is ...
500/0.0625 = c = 8000
and the sale price is ...
s = c +p = 8000 +500 = 8500 . . . rupees
The selling price will be Rs 8500.
