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jeka57 [31]
3 years ago
15

The original price of a car is $25000. Each year, its value depreciates (loses value) by 13%. Three years after its purchase, wh

at is the value of the car?
Mathematics
1 answer:
Thepotemich [5.8K]3 years ago
5 0

Answer:

$16,462.58

Step-by-step explanation:

25000(1-.13)^(n)

where n is the years

25000(.87)^3

put this into a calculator and get

16462.57

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What is f(-3) if f(x) = 12x + 11 + 5?
Zina [86]

Answer:

-20

Step-by-step explanation:

f (-3) = 12 x -3 + 11 +5

                          ^

          12 x -3  + 16

                ^

              -36 + 16

                     ^

                   = -20

6 0
3 years ago
How do you Simplify this expression5(x+1)-5x
Mariana [72]

Answer:

5

Step-by-step explanation:

Begin by removing the brackets.

5x + 5 - 5x

Notice that there are two 5xs. They are of opposite signs so they cancel

Answer 5

6 0
3 years ago
Read 2 more answers
Which angles below are complementary?
tigry1 [53]

9514 1404 393

Answer:

  ∠KXN and ∠QXT

Step-by-step explanation:

The measure of each angle is the difference of the scale values that the rays intercept. (The same scale needs to be used for each ray.) Of course, complementary angles have a sum of 90°.

Here, we'll refer to angle aXb as "ab".

  NP = 95 -35 = 60

  PQ = 35 -20 = 15  . . .  not complementary to NP

__

  KN = 165 -95 = 70

  QT = 20 -0 = 20  . . .  complementary to KN   ⇒ your answer

__

  JK = 180 -165 = 15

  PQ = 35 -20 = 15  . . . not complementary to JK

__

  JK = 15

  NK = KN = 70  . . .  not complementary to JK

6 0
2 years ago
Let the universal set be the set of integers and let A = {x | x^2 ≤ 5}. Write A using the roster method.
Zarrin [17]

Answer:

Step-by-step explanation:

Given that Z the set of integers is the universal set and

A is given in set builder form.

A = {x | x^2 ≤ 5}

To convert this into roster form, we can find solutions for x

When x^2\leq 5\\|x|\leq \sqrt{5} =2.236

i.e. all integers lying between -2.236 and 2.236

The only integers satisfying this conditions are

-2,-1,0,1,2

Hence A in roster form is

A={-2,-1,0,1,2}

8 0
3 years ago
A circle has a center at Left-parenthesis 3 comma 5 right-parenthesis. The point Left-parenthesis 3 comma 8 right-parenthesis is
svet-max [94.6K]
The correct answer for this question would be option B) 18.8 units or the second option.
5 0
3 years ago
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