Solve for x khan academy solve similar triangles advanced
1 answer:
Answer:
x = 10/3
Step-by-step explanation:
The question is incomplete without the diagram as this would enable us solve for x. Find attached the diagram used for solving the question.
We can tell from the question we are to compare two triangles drawn together (smaller one drawn in a bigger one) using similar triangles.
Using similar triangles to solve for x,
∆ABC = ∆ADE
∠CBA = ∠EDA = 90°
Let's relate the ratio of their corresponding sides.
(Adjacent/opposite) in ∆ABC
= (Adjacent/opposite) in ∆ADE
AB/CB = AD/ED
AB = 6
CB = 2
AD = AB + BD = 4+6 = 10
ED = x
6/2 = 10/x
3 = 10/x
3x = 10
x = 10/3
You might be interested in
A suitable probability app shows the 1st percentile to be at about 11040 pages.
_____
The app shown has an error in the first decimal digit. The number is closer to 11040.82301. We expect the manufacturer would round to the nearest 10 or 50 or 100 in advertising.
