O fosgenio e um gás asfixiado tóxico e com cheiro penetrante esse gás utilizado como arma na primeira guerra mundial era produzi
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Answer:
<h2>0.03 moles </h2>Explanation:
To find the number of moles in a substance given it's number of entities we use the formula
where n is the number of moles
N is the number of entities
L is the Avogadro's constant which is
6.02 × 10²³ entities
We have
We have the final answer as
<h3>0.03 moles </h3>Hope this helps you
Answer:
35.26 rad
Explanation:
Let's assume the cube in the figure below. If it's in the first octant, then origin (0, 0, 0) is one of the vertices and it's also the common vertex of the diagonals (OB and OE).
The point B is at the y-axis, so since the length is 8, it is (8, 0, 8), and the point E is (8, 8, 8). The vectors of the diagonals are the subtraction of the coordinates of the two points, so OB = <8, 0, 8> and OE = <8, 8, 8>. The angle between two vectors in the tridimensional space is:
θ = cos⁻¹[(OB · OE)/(|OB|·|OE|)]
The module (| |) of a vector <x, y, z> is √(x² + y² + z²)
θ = cos⁻¹[(<8, 0, 8> · <8, 8, 8>)/(√(8² + 0² + 8²) · √(8² + 8² + 8²))]
θ = cos⁻¹[(8*8 + 8*0 + 8*8)/(√128 ·√192)]
θ = cos⁻¹[128/156.77]
θ = cos⁻¹[0.8165]
θ = 35.26 rad
Answer:
17.95 g
Explanation:
The electrolysis of CaBr₂ → Ca²⁺ + 2Br⁻
Ca₂⁺ + 2e⁻ → Ca
Recall that:
Charge (Q) = current (I) × time (t)
Q = 10.0 × 2.4 × 3600
Q = 86400 C
Number of moles of electron =
No of moles of Ca =
= 0.44775 moles
Mass of Ca = no of moles × molar mass of Ca
= 0.44775 mol × 40.08 g/mol
= 17.95 g