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tamaranim1 [39]
3 years ago
6

A.Solid b.Liquid c.Gas d.Plasma

Chemistry
2 answers:
jonny [76]3 years ago
8 0

Answer

please add the question

Explanation:

White raven [17]3 years ago
4 0

Answer:

what was the question?

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The atomic number of Oxygen is 8. Therefore, which of the following answers would correspond to what would be in the nucleus of
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Answer:

Its official chemical symbol is O, and its atomic number is 8, which means that an oxygen atom has eight protons in its nucleus. ... Oxygen is normally found as a

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Nitric acid is a key industrial chemical, largely used to make fertilizers and explosives. The first step in its synthesis is th
kolbaska11 [484]

Answer: When using 645 L /s  of O2 in a temperature and pressure of  195°C,  0.88 atm  respectively, we will get 0.355Kg /s NO

Explanation:

  • First we review the equation that represents the oxidation process of the NH3 to NO.

4NH3(g) + 5O2(g) ⟶4 NO(g) +6 H2O(l)  

  • Second we gather the information what we are going to use in our calculations.

O2 Volume Rate = 645 L /s

Pressure = 0.88 atm

Temperature = 195°C + 273 = 468K

NO molecular weight = 30.01 g/mol  

  • Third, in order to calculate the amount of  NO moles produced by 645L/ s of O2, we must find out, how many moles (n) are 645L O2 by using the general gas equation PV =n RT

Let´s keep in mind that using this equation our constant R is 0.08205Lxatm/Kxmol

PV =n RT

n= PV / RT

n= [ 0.88atm x 645L/s] / [ (0.08205 Lxatm/Kxmol) x 468K]

n= 14.781 moles /s of O2

  • Fourth, now by knowing the amount of moles of O2, we can use the equation to calculate how many moles of NO will be produced and then with the molecular weight, we will finally know the total mass per second .

14.781 moles /s of O2 x 4moles NO / 5 moles O2 x  30.01g NO / 1 mol NO x 1Kg NO /1000g NO = 0.355Kg /s NO

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__________ solutions are very unstable.
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If the temperature of a reversible reaction in dynamic equilibrium decreases, how will the equilibrium change?
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D. It will shift towards the exothermic reaction.

Explanation:

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