Answer: 500L
Explanation:
No of moles= volume× molarity/1000
No of moles =0.5moles
Volume=?
Molarity of a gas at stp = 1M
Stp means standard temperature and pressure
No of moles = volume ×molarity/1000
Substitute the values
0.5=volume×1/1000
Cross multiply
Volume = 1000×0.5
Volume = 500L
The volume is 500L
Answer:
Knowing the mass of chlorine in each mixture will enable you find the empirical formulas that will lead to molecular formulas for the compounds in the mixture.This information will help you determine which mixture has a higher proportion of the compound in question.
Explanation:
In determining the percent composition of a compound in a mixture,mass of a compound will be the first step to be determined.This will then allow you to find mole to mole ratio of all elements in that compound.Having mole ratio information, and mass, it will be possible to find ratio of ions in the compound,and determine the mixture with higher proportion of the compound.
Molecular weight and the empirical formula of the compound will led you to the molecular formula of the compound,that will show you the mole ratios which now you can use to determine proportions of the compound in a mixture.
The answer is (3) metallic. Cobalt is a transition metal, so it can't be covalent bonds, which bond non-metals, therefore eliminating choice 1 and 2. Ionic bonds are between metals and non metals, but solid cobalt does not have a non metal, eliminating choice 4 as well. Metallic bonds are bonds between metals, therefore the answer is (3) metallic.
Answer:
A scalar quantity is a quantity that includes both magnitude (the number) and a unit, but not direction.
An example of this is 5m.
The question is incomplete,the complete question :
Calculate the molality of a 10.0% (by mass) aqueous solution of hydrochloric acid:
a) 0.274 m
b) 2.74 m
c) 3.05 m
d) 4.33 m
e) the density of the solution is needed to solve the problem
Answer:
The molality of a 10.0% (by mass) aqueous solution of hydrochloric acid is 3.05 mol/kg.
Explanation:
10.0% (by mass) aqueous solution of hydrochloric acid.
10 grams of HCl is present in 100 g of solution.
Mass of HCl = 10 g
Mass of solution = 100 g
Mass of solution = Mass of solute + Mass of water
Mass of water = 100 g - 10 g = 90 g
Moles of HCl = 
Mass of water in kilograms = 0.090 kg
Molality = 
The molality of a 10.0% (by mass) aqueous solution of hydrochloric acid is 3.05 mol/kg.
