Physicist Albert Einstein developed the famous equation shown below.

Chemistry

1 answer:

zaharov [31]3 years ago

3 0

E = mc2

Born on March 14, 1879, Albert Einstein is best known for developing the theory of relativity and the mass-energy equivalence formula E = mc2, often dubbed as 'the world's most famous equation'.

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A tablet of Pain Be Gone Aspirin, which had a mass of 1.213 g, was pulverized and 1.159 g were dissolved in 10.0 mL of ethyl alc

allochka39001 [22]

Answer:

Moles of NaOH that reacted: $n_{NaOH}=1.64*10^{-3}mol$

Explanation:

During the titration, all moles of NaOH added in the solution, react with the acetylsalicylic acid neutralizing each other.

The titration required 15.62 ml (0.01562 L) of the 0.1052 M NaOH solution. The moles of NaOH in that volume are:

$n_{NaOH}=0.01562 L * \frac{0.1052mol}{L}$

$n_{NaOH}=1.64*10^{-3}mol$

8 0

3 years ago

Provide an explanation at the subatomic level to explain why different colors are observed for different metal salts.

lakkis [162]

Answer:

When you heat an atom, some of its electrons are "excited* to higher energy levels. When an electron drops from one level to a lower energy level, it emits a quantum of energy. ... The different mix of energy differences for each atom produces different colours. Each metal gives a characteristic flame emission spectrum.

Explanation:

8 0

4 years ago

Read 2 more answers

Is this experiment okay for this question???? If not, what would a good one be?

Fed [463]

Yes that would be ok, explain how it works though.

6 0

4 years ago

How much heat is transferred when 7.19 grams of H2 reacts with excess nitrogen, according to the following equation: N2(g) + 3 H

nikdorinn [45]

Answer:

$Q=54.8kJ$

Explanation:

Hello there!

In this case, according to the given chemical reaction, it is possible for us to realize that the 46.2 kJ of energy are given per mole of reaction, which are related to 3 moles of hydrogen; Thus, we can calculate the energy per mole of hydrogen as shown below:

$\Delta H=\frac{46.2kJ}{mol} *\frac{1mol}{3molH_2}\\\\ \Delta H=15.4\frac{kJ}{molH_2}$