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3 years ago

What is the area of a circle with a diameter of 8

Mathematics

1 answer:

vlada-n [284]3 years ago

4 0

Step-by-step explanation:

Radius (R) =diameter /2 =8/2 =4

So area=

$\pir {r}^{2} = \pi {4}^{2} = 50.27$

Hope this helps..

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1. 1 +2r = 2. 12 = 18 - d 3. 5b + 10 = 30

seropon [69]

Answer:

1. r=anything

2. d=6

3. b=4

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

2x + 2y = -2 3x - 2y = 12 Solve By Elimination Pls give me the hole equation

Sholpan [36]

Answer:

x = 2

y = -3

Step-by-step explanation:

2x + 2y = -2, then 2y = -2 - 2x

3x - 2y = 12, then 2y = 3x - 12

so:

-2 - 2x = 3x - 12

add 2x and 12 to each side of the equation:

5x = 10

divide both sides by 5:

x = 2

2y = 3(2) - 12

2y = -6

divide both sides by 2:

y = -3

8 0

3 years ago

A line passes through the point (-10,8) and has a slope of 1/2.

timofeeve [1]

Answer:

the answer is y=1/2x+13

6 0

3 years ago

Write an equation that is perpendicular to and 3x+y=3 whose y-intercept 5. Anyone please help me, no link just explain how to do

Liula [17]

Answer:

$y = \frac{1}{3}x + 5$

Step-by-step explanation:

By definition, two lines are perpendicular if and only if their slopes are negative reciprocals of each other: $m = - \frac{1}{m_{2} }$ , or equivalently, $m_{1} * m_{2} = -1$ .

Given our linear equation 3x + y = 3 (or y = -3x + 3):

We can find the equation of the line (with a y-intercept of 5) that is perpendicular to y = -3x + 3 by determining the negative reciprocal of its slope, -3, which is $\frac{1}{3}$ .