Start by using trig to find the length of the line LJ
The triangle KJL (big right angled triangle) has been given the following dimensions
Hypotenuse =

The adjacent angle is 30 degrees
Since we have the hypotenuse and the angle we must use the equation
opposite = Sin(angle) x Hypotenuse
Opposite= sin30 x

Opposite=

Therefore line LJ is

Now look at the smaller right angled triangle (LMJ)
Hypotenuse is the line LJ which is

The adjacent angle is 45
Since we have hypotenuse and angle we must use the equation opposite = sin(angle) * h
therefore
x=

* sin45= 4
Find values that add to 5 and multiply to 6
so the answer would be (x+5)(x+1)
The <u>rise</u> is the difference in y-coordinates:
The <u>run</u> is the difference in x-coordinates:
The <u>slope</u> is the quotient of rise over run:
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If two points on a line are A(10, −3) and B(12, 9), the rise is <u>12</u>, and the run is <u>2</u>, so the slope of the line is <u>6</u>.
Hi,
c=4, b=2, a²=b²+c²==> a=2√5
A straight line adds up to 180
So the line opposite of 137 should add up to 180
This gives us the equation 137+x=180 then x=43
The triangle also adds up to 180 degrees
So 102+43+x=180
The equation can be simplified to 145+x=180 therefore x=35
So x+?=180 because it is a straight line.
We can substitute x in making the equation 35+?=180
Now we want to solve for the ? so we'll subtract 35 from each side
This leaves us with the equation ?=145
So we now know that the ?=145