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3 years ago

Find the distance between (3,7) and (6,5)

Mathematics

1 answer:

zubka84 [21]3 years ago

8 0

Answer:

square root of five but if it needs to be simplified then 2.24 (rounded)

Step-by-step

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Use the quadratic formula to solve 5x=6x^2-3, what are the values of x?

Elis [28]

5x= 6x^2 -3
6x^2 -5x -3
a = 6
b = -5
c = -3

x = [-b +- sq root(b^2 -4ac)] / 2a
x = [--5 +- sq root (25 -(4*6*-3)] / 12
x = [5 +- sq root (25 + 72)] / 12
x = [5 + sq root (97)] / 12
x = 5 +- 9.84886] / 12
x1 = 1.237405 
x2 = -0.404072

8 0

3 years ago

cable costs $50 for installation and $100 a month. satellite costs $200 for installation and $70 a month. what month will the co

sdas [7]

Answer: The cost will be the same on month 5.

Step-by-step explanation:

x = number of months

50 + 100(x) = $550

200 + 70(x) = $550

x = 5

5 0

3 years ago

Read 2 more answers

R is the midpoint of PQ. PR = 6x + 7 and RQ = 3x + 8, find the length of PQ.

Ksivusya [100]

Answer:

PQ = 18

Step-by-step explanation:

If R is the midpoint of PQ, then PR = RQ

⇒ 6x + 7 = 3x + 8

⇒ 3x = 1

⇒ x = 1/3

So PR = 6x + 7 = 6(1/3) + 7 = 9

and RQ = 3x + 8 = 3(1/3) + 8 = 9

⇒ PQ = PR + RQ = 9 + 9 = 18

6 0

2 years ago

Help plz!!!!!!!!!!!!!!!!!!

kvasek [131]

Answer:

n*8=24

Step-by-step explanation:

3*8=24

7 0

2 years ago

Read 2 more answers

your grades on tests 1 2 and 4 are 82 76 and 90. unfortunately you cut the third test and received a 0. If you have one test lef

Dmitrij [34]

Answer: No, he can't pass the course.

Explanation:

Since we have given that

Marks on tests 1, 2, and 4 are given by

82, 76, 90 respectively.

Unfortunately, he cut the third test and receive a 0.

According to question, we have given that passing grade for the course is 70, and his one test left to take ,

Let the marks obtained in fifth test be x

So,

$\frac{82+76+90+0+x}{5}=70\\\\248+x=5\times 70=350\\\\x=350-248\\\\x=102$

And it is not possible to get 102 over 100.

so, he can't still pass the course.

Hence, No, he can't pass the course.

8 0

3 years ago