I think you forgot to put the options but it would be 4b
hope this helps you!
Answers:
1) (s o t)(x)=4x^2-x-4
2) (t o s)(x)=4(x-7)^2-(x-7)+3
Solution:
1) (s o t)(x)=s(t(x))=s(4x^2-x+3)=(4x^2-x+3)-7=4x^2-x+3-7
(s o t)(x)=4x^2-x-4
2) (t o s)(x)=t(s(x))=t(x-7)=4(x-7)^2-(x-7)+3
(t o s)(x)=4(x-7)^2-(x-7)+3
Answer:
Standard form = y = mx + c
m = Δy/Δx
m = 5/2
y = 5/2 x + c
Sub in (4,2)
2 = 10 + c
c = -8
y = 5/2 x - 8
Step-by-step explanation:
Answer:
hpe it helps have a nice day dear
Ax² + bx + c = 0
2x² + x - 3 = 0
2x² + x + (-3) = 0
x = <u>-b +/- √b² - 4ac</u>
2a
x = <u>1 + /- √1² - 4(2)(-3)</u>
2(2)
x = <u>1 + /- √1 +24</u>
4
x = <u>1 +/- √25
</u> 4<u>
</u>x = <u>1 + /- 5
</u> 4<u>
</u>x = <u>1 + 5</u> x = <u>1 - 5
</u> 4 <u> </u> 4<u>
</u>x = <u>6</u> x = <u>-4</u>
4 4
x = <u>3</u> x = -1
2
x = 1 1/2
x = 1 1/2 x = -1