It will take B 8 hours to travel in order to overtake A.
The relationship among the distance, time and speed can be expressed by using the relation.
In this kind of ratio relation, it is pertinent to understand that, the rise in a variable cause a decrease in the other, where the third variable is constant.
Here:
- as speed (v) rises;
- time (t) decreases, and
- distance (d) is constant
From the given relation:
So, we can have a table expressing the parameters given in the question as follows:
v t d
A 4 t+2 4t + 8
B 5 t 5t
Equating both distance together, we have:
4t + 8 = 5t
collecting like terms, we have:
4t - 5t = -8
t = 8 hours
Therefore, we can conclude that it will take B 8 hours to travel in order to overtake A.
Learn more about distance, time and speed here:
brainly.com/question/12199398
Answer:
10x -18
Step-by-step explanation:
add the same things together
W-1/4= 3/7
W-1/4+1/4= 3/7+1/4
find the common denominator for the fractions
common denominator is 28
Multiply by 4 , top and bottom for 3/7
Multiply by 7 , top and bottom for 1/4
W= 12/28+7/28
W= 19/28
Answer is W= 19/28
Answer:
Most people found the probability of just stopping at the first light and the probability of just stopping at the second light and added them together. I'm just going to show another valid way to solve this problem. You can solve these kinds of problems whichever way you prefer.
There are three possibilities we need to consider:
Being stopped at both lights
Being stopped at neither light
Being stopped at exactly one light
The sum of the probabilities of all of the events has to be 1 because there is a 100% chance that one of these possibilities has to occur, so the probability of being stopped at exactly one light is 1 minus the probability of being stopped at both lights minus the probability of being stopped at neither.
Because the lights are independent, the probability of being stopped at both lights is just the probability of being stopped at the first light times the probability of being stopped at the second light. (0.4)(0.7) = 0.28
The probability of being stopped at neither is the probability of not being stopped at the first light, which is 1-0.4 or 0.6, times the probability of not being stopped at the second light, which is 1-0.7 or 0.3. (0.6)(0.3) = 0.18
The probability at being stopped at exactly one light is 1-0.18-0.28=.54 or 54%.
I would say C. and A. Hope this helps.
