Question

Which equation represents a line that passes through (–9, –3) and has a slope of –6?

Answer 1

Answer:

The required equation of line is y=-6x-57.

Step-by-step explanation:

The point slope form of a line is

$y-y_1=m(x-x_1)$

Where m is slope of the line.

It is given that a line that passes through (–9, –3) and has a slope of –6.

Substitute m=-6, x₁=-9 and y₁=-3 in the above equation.

$y-(-3)=-6(x-(-9))$

$y+3=-6x-54$

Subtract 3 from both the sides.

$y=-6x-54-3$

$y=-6x-57$

Therefore the required equation of line is y=-6x-57.

Answer 2

Answer:

D).y+3=-6(x+9)

Step-by-step explanation:

took it on edge