Since Doug’s brother has double the amount of Doug we can just multiply the amount Doug has by 2.
$3,215*2 = $6,430
Answer: Dylan weighs 45 pounds while Alan weighs 93 pounds.
Answer:
38 quarters
Step-by-step explanation:
0.25 x 63 = 15.75
0.05 x 63 = 3.15
----------------------------
0.25 x 50 = 12.50
+ = $13.15
0.05 x 13 = 0.65
----------------------------
0.25 x 25 = 6.25
+ = $8.15
0.05 x 38 = 1.90
----------------------------
0.25 x 30 = 7.50
+ = $9.15
0.05 x 33 = 1.65
--------------------------
0.25 x 35 = 8.75
+ = $10.15
0.05 x 28 = 1.40
-------------------------
0.25 x 38 = 9.50
+ = $10.75
0.05 x 25 = 1.25
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I hope this helps!
Answer:
32
Step-by-step explanation:
It is given that Jeff and his friend each text four classmates about an concert that is two people texts four classmates then 2×4=8 people are notified about the concert, then according to question, each 8 of them texts 4 more students from a different school about the concert, so the total number of people from the other school which are being notified about the concert will be 8×4=32.
Answer:
C
Step-by-step explanation:
This problem is analogous to the extraction of 6 elements from a total of 10 elements. It's the same if they are marbles, chips, or in this case, people, as here we don't care about the order of the selection as we only are drawing a sample.
Thus, the problem implies solving the amount of possible combinations of 10 people if we take by 6. There is a formula for this and is:
10 C 6 = 10!(6!4!)
If we operate, knowing that for any number x, x!=x*(x-1)*(x-2)*...*1
10 C 6 = 10!(6!4!) = 10*9*8*7*6*...*1 / [(6*5*...*1) * (4*3*2*1)]
10 C 6 = 10*9*8*7*6! / [(6*5*...*1) * (4*3*2*1)]
We have a 6! multiplying and another dividing, so they get eliminated, and as 4*2=8 and 9=3*3
10 C 6 = 10*9*8*7*/ [(4*3*2*1)] = 10*3*3*8*7*/ [(8*3*1)]
We can eliminate the 8s and one of the 3s on the numerator with the one on the denominator:
10 C 6 = 10*3*7*/1 = 210/1= 210
So, option C
