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2 years ago

13 = r/12 solve for r

1 answer:

3 0

13 = r/12, first to cancel 12 and leave r alone you multiply it by 12 and it cancels and whatever you do on one side you do to the other. So you multiply 13 times 12 too.

You are then left with, 13•12 = r
Which is 156

Therefore,

r = 156

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Wrong answers will be reported

PIT_PIT [208]

The solution to the equation is p = 1/3 and q = undefined

<h3>How to solve the equation?</h3>

The equation is given as:

p^2 - 2qp + 1/q = (p - 1/3)

The best way to solve the above equation is by the use of a graphing calculator i.e. graphically

However, it can be solved algebraically too (to some extent)

Recall that the equation is given as:

p^2 - 2qp + 1/q = (p - 1/3)

Split the equation

So, we have

p^2 - 2qp + 1/q = 0

p - 1/3 = 0

Solve for p in p - 1/3 = 0

p = 1/3

Substitute p = 1/3 in p^2 - 2qp + 1/q = 0

So, we have

(1/3)^2 - 2q(1/3) + 1/q = 0

This gives

1/9 - 2/3q + 1/q = 0

This gives

2/3q + 1/q = -1/9

Multiply though by q

So, we have

2/3q^2 + 1 = -1/9q

Multiply through by 9

6q^2 + 9 = -q

So, we have

6q^2 + q + 9 = 0

Using the graphing calculator, we have

q = undefined

Hence. the solution to the equation is p = 1/3 and q = undefined

Read more about equations at:

brainly.com/question/13763238

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5 0

1 year ago

The given statement is true or t<br> (-4+6i)-(12-5i) = -16+ i

Pavel [41]

The answer is x=mc^2

8 0

1 year ago

Read 2 more answers

rhombus has sides of length 10 cm. and the angle between two adjacent sides is 76 degrees. Find the lengths of the other diagona

lisabon 2012 [21]

Let the length of one of the diagonals be 2x and the other be 2y, then
cos (76/2) = x/10
x = 10 cos 38 = 7.88 cm

sin (76/2) = y/10
y = 10 sin 38 = 6.16 cm

3 0

3 years ago

Which unit of measurement would be appropriate for the volume of a sphere with a radius of 2 meters

Semenov [28]

The volume of a sphere is found with the following formula:

$V = \frac{4}{3}\pi r^3$

The radius is raised to a power of 3. Since the radius is 2 <em>meters</em>, this means that the volume would be measured in cubic meters.

3 0

3 years ago

7. The largest of the Great Pyramids in Egypt was built with a square base,

strojnjashka [21]

Answer:

Difference between the original and current volumes = 4013140.30 cubic feet

Step-by-step explanation:

Largest pyramid has the square base with one edge = 754 feet

Area of the square base = (Side)²

= (754)²

= 568516 square feet

Volume of the pyramid = $\frac{1}{3}(\text{Area of the base})(\text{Height})$

= $\frac{1}{3}\times 568516\times 481$

= 91152065.3 cubic feet

After erosion,

Area of the base = (745)² = 555025 square feet

Volume of the pyramid = $\frac{1}{3}(555025)(471)$

= 87138925 cubic feet

Difference between the original and current volumes of the pyramid

= 91152065.30 - 87138925

= 4013140.30 cubic feet

5 0

3 years ago