Answer:
The function in the form of fog(x) is written as 48 x² + 336 x + 590
Step-by-step explanation:
Given function as :
f(x) = 3 x² - 6 x + 5
g(x) = - 4 x - 13
So, The function in the form of fog(x) is written as
We, substitute the value of g(x) into f(x)
∴ fog(x) = 3 (g(x))² - 6 (g(x)) + 5
Or, fog(x) = 3 (- 4 x - 13 )² - 6 ( - 4 x - 13 ) + 5
or, fog(x) = 3 (16 x² + 169 + 104 x) + 24 x + 78 + 5
or , fog(x) = 48 x² + 507 + 312 x + 24 x + 78 + 5
or , fog(x) = 48 x² + 336 x + 590
So, The function in the form of fog(x) = 48 x² + 336 x + 590
Hence The function in the form of fog(x) is written as 48 x² + 336 x + 590 Answer
The effect on the graph of f(x)= 1/x when it is transformed to g(x)= 1/x-7 is C. The graph of f(x) is shifted 7 units down.
<h3>What is a graph?</h3>
A graph is a diagram showing the relation between variable quantities, each measured along with one of a pair of axes at right angles.
In this case, the effect on the graph of f(x)= 1/x when it is transformed to g(x)= 1/x-7 is that the graph of f(x) is shifted 7 units down.
The missing options include:
A. The graph of f(x) is shifted 7 units up
B. The graph of f(x) is shifted 7 units to the left
C. The graph of f(x) is shifted 7 units down
D. The graph of f(x) is shifted 7 units to the right.
Learn more about graph on:
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Answer:
Step-by-step explanation:
To differentiate this we will need to use the chain rule:
![[h(g(x))]'=g'(x) \cdot h'(g(x))](https://tex.z-dn.net/?f=%5Bh%28g%28x%29%29%5D%27%3Dg%27%28x%29%20%5Ccdot%20h%27%28g%28x%29%29)
.
We will also have to keep in mind how to differentiate the following:
with repect to 
with respect to 
.
Derivative of both sides:
