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Nina [5.8K]
2 years ago
8

Which one is it A B C D

Mathematics
1 answer:
vovangra [49]2 years ago
3 0

Answer:B

Step-by-step explanation: Alternate exterior angles theorem

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An ion channel can be in either open (O) or closed (C) states. If it is open, then it has probability 0.1 of closing in 1 micros
iragen [17]

Answer:

a)  P (COO)  = 0,135

b) P ( SISI) = 0,00015

Step-by-step explanation:

a) the probability of an ion channel in open position is 50 %   0,5

   the probability of an ion channel in close position is 50 %   0,5

probability for the following sequence of states COO

to be closed   0,5    (C)

from (C) to pass to open  0,3  (O)

and to stay O  is 0,9

Then the probability of the sequence of states COO is

P (COO)  = 0,5 * 0,3 * 0,9  

P (COO)  = 0,135

b) If people are either infected or susceptible, then

Probability of an individual infected is  0,5

Probability of an individual susceptible  is 0,5

to pass from susceptible to infected is 0,05

to pass from infected to susceptible is 0,12

then

P ( SISI) = 0,5 * 0,05*0,12*0,05

P ( SISI) = 0,00015

probability for the following sequence of states COO

4 0
3 years ago
PLEASE HELP ANYONE
LUCKY_DIMON [66]
For this problem all you have to do is plug in the value that they is in parenthesis for x. If it says g (x) = x and then it asks g(5) = ?, it is saying what happens if i put 5 in for every x. in this case it would be g (5) = 5. I just replaced x with 5.

So g (-2) we sub -2 for x
g (-2) = -2 (-2)^2 + 3 (-2) - 5
= -2 (4) - 6 - 5
= -19

g (0) = -2 (0) + 3 (0) - 5
= 0 + 0 - t
= -5

g (3) = -2 (3)^2 + 3 (3) - 5
= -18 + 9 - 5
= -14
6 0
3 years ago
Find the first five terms of the sequence in which a1 = 6 and an = –3an – 1 – 12, if n ≥ 2.
maxonik [38]

Answer:

Step-by-step explanation:

so whats the answer?

5 0
3 years ago
Can someone help me in #66
VladimirAG [237]
\bf log_{{  a}}(xy)\implies log_{{  a}}(x)+log_{{  a}}(y)
\\ \quad \\
% Logarithm of rationals
log_{{  a}}\left(  \frac{x}{y}\right)\implies log_{{  a}}(x)-log_{{  a}}(y)
\\ \quad \\
% Logarithm of exponentials
log_{{  a}}\left( x^{{  b}} \right)\implies {{  b}}\cdot  log_{{  a}}(x)\\\\
-------------------------------\\\\


\bf log_4\left( \cfrac{\sqrt{x^5y^7}}{zw^4} \right)\implies log_4(\sqrt{x^5y^7})-log_4(zw^4)
\\\\\\
log_4\left[(x^5y^7)^{^\frac{1}{2}}\right]-log_4(zw^4)\implies 
\cfrac{1}{2}log_4\left[(x^5y^7)\right]-log_4(zw^4)
\\\\\\
\cfrac{1}{2}\left[ log_4(x^5)+log_4(y^7) \right] -[log_4(z)+log_4(w^4)]
\\\\\\
\cfrac{1}{2}log_4(x^5)+\cfrac{1}{2}log_4(y^7)-[log_4(z)+log_4(w^4)]

\bf \cfrac{1}{2}\cdot 5log_4(x)+\cfrac{1}{2}\cdot 7log_4(y)-log_4(z)-4log_4(w)
\\\\\\
\cfrac{5}{2}log_4(x)+\cfrac{7}{2}log_4(y)-log_4(z)-4log_4(w)
6 0
3 years ago
Find the missing exponent in each expression
Naily [24]

Answer:

See below.

Step-by-step explanation:

Multiplying terms with exponents make the exponents add together.

13.) x² · x⁵ = x⁷

14.) b⁵ ·  b³ = b⁸

15.) y⁴ · y⁷ = y¹¹

16.) m⁴ · m¹ = m⁵

8 0
3 years ago
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