The <u>different</u> selections of<u> one</u> meat and <u>one</u> vegetable are possible are 18 selections.
Since the Hickory Stick has a selection of 3 meats and 6 vegetables, the number of ways we can select <u>one </u>meat out of 3 is ³C₁ = 3.
Also, the number of ways we can select <u>one </u>vegetable out of 6 is ⁶C₁ = 6.
So, the total number of selections of <u>one</u> meat and <u>one</u> vegetable is ³C₁ × ⁶C₁ = 3 × 6
= 18 selections
So, the <u>different</u> selections of<u> one</u> meat and <u>one</u> vegetable are possible are 18 selections.
Learn more about combination here:
brainly.com/question/19341024
The area of each of the 4 triangles is
... A = (1/2)bh = (1/2)(4)(3) = 6
The area of the square base (in the center of the net diagram) is
... A = s² = 4² = 16
Then the total area is 4×6 + 16 = 40 square units.
Answer:
an+4n+1
Step-by-step explanation:
Hope it helped
It’s the strawberry and orange one
