95,438 - 62,804= 30,000 when rounded
Let Xavier's favourite fraction be a/b, Yessie's favourite fraction = b/a and Zorro's favourite fraction = c/d,
c/d x a/b = 12/35 . . . . . . . . (1)
c/d x b/a = 15/7 . . . . . . . . (2)
(1) x (2) = c/d x a/b x c/d x b/a = 12/35 x 15/7
c^2 / d^2 = 36/49
c^2 = 36
c = 6
d^2 = 49
d = 7
Xaviers favourite fraction = 12/35 / 6/7 = 2/5
Yessies favourite fraction = 5/2
Zorro favourite fraction = 6/7
a.
In order to find the common ratio, we just need to divide a term by the term that comes before it.
So using the terms 20 and -5, we have:
b.
The recursive rule can be found with the formula:
Where an is the nth term and q is the ratio. So we have:
c.
The explicit rule can be written as:
Where an is the nth term, a1 is the first term and q is the ratio. So:
Pretty sure it’s the second option because length would be 3w+2
and width would be w+1 and with area you have to multiply so it would just be the (w+1)(3w+2)
Given:
10 yards required
5 2/3 yards on hand.
We need to subtract the yards on hand from the total yards required.
First, we need to convert the mixed fraction into an improper fraction.
5 2/3 = ((5*3)+2)/3 = (15+2)/3 = 17/3
Second, we need to multiply 10 by a fraction that will give us the denominator of 3.
10 * 3/3 = (10*3)/3 = 30/3
Third, we do subtraction using our derived fractions.
30/3 - 17/3 = (30-17)/3 = 13/3
Lastly, we simplify the improper fraction. Improper fraction is a fraction whose numerator is greater than its denominator. Its simplified form is a mixed fraction.
13/3 = 4 1/3
Arliss needs to buy 4 1/3 yards more to complete the required yard length.
