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scZoUnD [109]
3 years ago
12

The expression cos(A-B) - cos(A+B) is equal to

Mathematics
2 answers:
olchik [2.2K]3 years ago
6 0
Cos (A-B) - cos (A+B) 
= (cosAcosB +sinAsinB) - (cosAcosB - sinAsinB)
=2sinAsinB

Ans: 4
tigry1 [53]3 years ago
4 0
Cos (A+B)=cos (A) cos( B)-sin (A) sin (B)
cos (A-B)=cos (A) cos (B)+sin (A)sin (B)

Then:
cos (A-B)-cos (A+B)=
[cos (A) cos (B)+sin (A)sin (B)]-[cos (A) cos( B)-sin (A) sin (B)]=
cos (A) cos( B)+sin (A) sin (B)-cos (A) cos( B)+sin (A) sin (B)=
sin (A)sin (B)+Sin (A)sin(B)=
2sin (A)sin (B)

Answer: 4) 2sin (A)sin (B)


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Answer:

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Step-by-step explanation:

From Linear Algebra, we define the dilation of a point by means of the following definition:

G'(x,y) = O(x,y) +k\cdot [G(x,y)-O(x,y)] (1)

Where:

G(x,y) - Coordinates of the point G, dimensionless.

O(x,y) - Center of dilation, dimensionless.

k - Scale factor, dimensionless.

G'(x,y) - Coordinates of the point G', dimensionless.

If we know that O(x,y) = (0,0), G(x,y) =(2,-2) and G'(x,y) =(5,-5), then scale factor is:

(5,-5) = (0,0) +k\cdot [(2,-2)-(0,0)]

(5,-5) = (2\cdot k, -2\cdot k)

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The dilation on any point of the rectangle is P'(x,y) = \frac{5}{2}\cdot P(x,y).

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