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2 years ago

The expression cos(A-B) - cos(A+B) is equal to

Mathematics

2 answers:

olchik [2.2K]2 years ago

6 0

Cos (A-B) - cos (A+B)
= (cosAcosB +sinAsinB) - (cosAcosB - sinAsinB)
=2sinAsinB

Ans: 4

tigry1 [53]2 years ago

4 0

Cos (A+B)=cos (A) cos( B)-sin (A) sin (B)
cos (A-B)=cos (A) cos (B)+sin (A)sin (B)

Then:
cos (A-B)-cos (A+B)=
[cos (A) cos (B)+sin (A)sin (B)]-[cos (A) cos( B)-sin (A) sin (B)]=
cos (A) cos( B)+sin (A) sin (B)-cos (A) cos( B)+sin (A) sin (B)=
sin (A)sin (B)+Sin (A)sin(B)=
2sin (A)sin (B)

Answer: 4) 2sin (A)sin (B)

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Here we can first find the area of yard and then subtract the area of vegetable garden to get the required area.

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Read 2 more answers

Let f(x)=2x+3 and g(x)=x×x-1 find a. f(g(x)) b.g(f(x))

Talja [164]

Answer:

See explanations below

Step-by-step explanation:

Given the functions f(x)=2x+3 and g(x)=x^2-1

a. Find f(g(x))

f(g(x)) = f(x^2-1)

f(g(x)) = 2(x^2-1)+3

f(g(x))= 2x^2-2+3

f(g(x)) = 2x^2+1

Hence the composite function f(g(x)) is 2x^2+1

b) g(f(x)) = g(2x+3)

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Vesnalui [34]

Answer:

Mario worked from

8:25 to 12:45 yesterday

11:20 to 3:10 today

To find the total time of work

12:45

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again

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Therefore

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