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Andreyy89
2 years ago
11

Need help w this problem

Mathematics
1 answer:
Bingel [31]2 years ago
5 0

Answer:

<h3>9, 18</h3>

Step-by-step explanation:

The key word "<u>product</u>" tells us to <u>multiply</u>.

And, you probably know, but "<em>integer</em>" just means "<em>number</em>".

The question is, essentially:
A × B = 162 where A is half of B.

As someone who was never gifted in math, my best suggestion for something like this is to grab a calculator and start dividing 162 by all the numbers below 10. You will know you've got your answer when the calculator gives you a number that is twice the number you divided by.

In this case, I divided 162 by 9 and got 18. Since 9 is half of 18, and multiplied they make 162, we know this is the correct answer.

Hope this helps

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4. -9/4
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Louisa Hight 7 miles of a 21 mile trail what percent of the trail did she hike
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There are two machines available for cutting corks intended for use in wine bottles. The first produces corks with diameters tha
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Answer:

0.6826 = 68.26% probability that the first machine produces an acceptable cork.

0.933 = 93.3% probability that the second machine produces an acceptable cork.

The second machine is more likely to produce an acceptable cork.

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

What is the probability that the first machine produces an acceptable cork?

The first produces corks with diameters that are normally distributed with mean 3 cm and standard deviation 0.10 cm, which means that \mu = 3, \sigma = 0.1

Acceptable between 2.9 and 3.1, which means that this probability is the pvalue of Z when X = 3.1 subtracted by the pvalue of Z when X = 2.9.

X = 3.1

Z = \frac{X - \mu}{\sigma}

Z = \frac{3.1 - 3}{0.1}

Z = 1

Z = 1 has a pvalue of 0.8413

X = 2.9

Z = \frac{X - \mu}{\sigma}

Z = \frac{2.9 - 3}{0.1}

Z = -1

Z = -1 has a pvalue of 0.1587

0.8413 - 0.1587 = 0.6826

0.6826 = 68.26% probability that the first machine produces an acceptable cork.

What is the probability that the second machine produces an acceptable cork? (Round your answer to four decimal places.)

For the second machine, we have that \mu = 3.04, \sigma = 0.04. Same probability we have to find out. So

X = 3.1

Z = \frac{X - \mu}{\sigma}

Z = \frac{3.1 - 3.04}{0.04}

Z = 1.5

Z = 1.5 has a pvalue of 0.9332

X = 2.9

Z = \frac{X - \mu}{\sigma}

Z = \frac{2.9 - 3.04}{0.04}

Z = -3.5

Z = -3.5 has a pvalue of 0.0002

0.9332 - 0.0002 = 0.933

0.933 = 93.3% probability that the second machine produces an acceptable cork.

Which machine is more likely to produce an acceptable cork?

Second one has a higer probability, so it is more likely to produce an acceptable cork.

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