Julie jogs 0.75miles each time. set 'x' to represent the unknown number of times. Total distance for the day is 6 miles. So, you multiply the distance of each run 0.75 times 'x' (unknown number of runs) and set this equal to 6 miles.
0.75x = 6 (divide each side by 0.75)
8 = x
She ran 8 times each day.
Answer:
459.9ft
Step-by-step explanation:
height = tanx * b where x is the angle of elevation and b is the distance from the base
It would be perpendicular
Answer:
A.99.7%
Step-by-step explanation:
We are given;
- Mean of a distribution, μ as 0.68 ounce
- Standard deviation, σ as 0.02 ounce
- The range values of X between 0.62 ounce and 0.74 ounce
We are required to calculate the percentage of the weight to be between 0.62 ounce and 0.74 ounce
Step 1: Calculate the Z-score
To get the Z-score we use the formula;
Z-score = (x-μ)/σ
Therefore, when x = 0.62
Then z score = (0.62 - 0.68 ) ÷ 0.02
= -3
When, x = 0.74
Then, Z score = (0.74 - 0.68) ÷ 0.02
= 3
Step 2: we use the Z-score table or the empirical rule
Using the Z-score table;
P(-3 < z < 3) = 99.7%.
Therefore; the percentage of mice that weigh between 0.62 ounce and 0.74 ounce is 99.7%.
Answer:
B and C
Step-by-step explanation:
