Answer:
y= ⅓x +2
Step-by-step explanation:
Since the graph is a linear graph, let's use the slope-intercept form to find its equation.
<u>Slope-intercept </u><u>form</u>
y= mx +c, where m is the slope and c is the y-intercept.
The y-intercept is the point at which the graph cuts through the y-axis. In this case, the y-intercept is 2.
Thus, y= mx +2.
Let's find the slope of the graph.
First, identify 2 pairs of coordinates from the graph:
(0, 2) and (3, 3)
Next, substitute these coordinates into the slope formula below:

slope


Thus, the equation of the graph is y= ⅓x +2.
If you interpret the question as is, the answer is in the thousands, which is not listed. The last part of the question should read 'the number of new cases doubled from those newly identified cases from the day prior. The question is very poorly phrased.
Day 1 : 5
Day 2: 5 + 10
Day 3: 15 + 20
Day 4: 35 + 40
Day 5: 75 + 80
Day 6: 155 + 160
Which is 315 at the end of 6th day
Using the normal distribution, the areas to the left are given as follows:
a) 0.7910.
b) 0.6664.
c) 0.3707.
d) 0.8508.
<h3>Normal Probability Distribution</h3>
The z-score of a measure X of a normally distributed variable with mean
and standard deviation
is given by:

- The z-score measures how many standard deviations the measure is above or below the mean.
- Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X, and is also the area to the left of Z.
Hence:
- The area to the left of Z = 0.81 is of 0.7910.
- The area to the left of Z = 0.43 is of 0.6664.
- The area to the left of Z = -0.33 is of 0.3707.
- The area to the left of Z = 1.04 is of 0.8508.
More can be learned about the normal distribution at brainly.com/question/4079902
#SPJ1
Answer:
Parabola
Step-by-step explanation:
When only one variable is squared, the conic is a <em>parabola</em>.
_____
both squared, same sign, same coefficient: circle
both squared, same sign, different coefficients: ellipse
both squared, different signs: hyperbola
Answer:
# 1 reb #2 is cfs
hope i could help...........