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krek1111 [17]
3 years ago
8

What are the x- and y- coordinates of point P on the directed line segment from K to J such that P is Three-fifths the length of

the line segment from K to J
Mathematics
1 answer:
Mrrafil [7]3 years ago
7 0

Answer:

\left ( \frac{3x_2+5x_1}{8},\frac{3y_2+5y_1}{8} \right )

Step-by-step explanation:

Given: P is Three-fifths the length of the line segment from K to J

To find: x- and y-coordinates of point P on the directed line segment from K to J

Solution:

Section formula:

Let point K and J be (x_1,y_1)\,,\,(x_2,y_2) such that the point p(x,y) divides KJ in ratio m:n

Then coordinates of point  P are given by \left ( \frac{mx_2+nx_1}{m+n},\frac{my_2+ny_1}{m+n} \right )

Take m:n=3:5

So,

coordinates of point P = \left ( \frac{3x_2+5x_1}{3+5},\frac{3y_2+5y_1}{3+5} \right )=\left ( \frac{3x_2+5x_1}{8},\frac{3y_2+5y_1}{8} \right )

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What is the value of a? 5 units 5 and one-third units 6 and two-thirds units 7 units
blagie [28]

The missing figure is attached

The value of a is 5\frac{1}{3} ⇒ 2nd answer

Step-by-step explanation:

Let as revise the Pythagoras Theorem

In the right triangle ABC, where ∠B is a right angle (AC is the hypotenuse, Ab and BC are the legs of the right angle)

  • (AC)² = (AB)² + (BC)²
  • (AB)² = (AC)² - (BC)²
  • (BC)² = (AC)² - (AB)²

If BD is drawn perpendicular to AC, we can use these rules

  • (AB)² = AD × AC
  • (BC)² = CD × AC
  • (BD)² = AD × CD
  • AB × BC = BD × AC

In Δ WYZ

∵ m∠WYZ = 90°

- By using Pythagoras Theorem

∴ (WZ)² = (WY)² + (YZ)²

∵ WY = 4 units

∵ YZ = 3 units

∵ WZ = c units

∴ c² = (4)² + (3)²

∴ c² = 16 + 9 = 25

- Take √ for both sides

∴ c = 5

In Δ XWZ

∵ m∠XWZ = 90°

∵ WY ⊥ XZ

- We can use the rule (WZ)² = ZY × ZX

∵ (WZ)² = ZY × ZX

∵ WZ = 5 units

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∵ ZX = (3 + a) units

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- Subtract 9 from both sides

∴ 16 = 3a

- Divide both sides by 3

∴ a = 5\frac{1}{3}

The value of a is 5\frac{1}{3}

Learn more:

You can learn more about the rules of the right triangle in brainly.com/question/14390928

#LearnwithBrainly

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