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Elenna [48]
3 years ago
10

(chemistry)calculate pH a solution containing 1 grams of nitric acid in 100 mL of water

Chemistry
1 answer:
Oliga [24]3 years ago
6 0

Answer:

jdksyeuueueuueueuueueudyydheyehhdhdhdhdhhdhdhdhjjdj

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What is the limiting reactant
hoa [83]

Answer:

refer to this site it has information about limiting reactant -

https://chem.libretexts.org/Bookshelves/Inorganic_Chemistry/Supplemental_Modules_(Inorganic_Chemistry)/Chemical_Reactions/Limiting_Reagents

4 0
3 years ago
What is sound? it is a form of energy produced by ____________.
Tpy6a [65]

Answer:

D

Explanation:

sound is produced when the matter vibrates

5 0
3 years ago
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Which flow chart is accurate?
djverab [1.8K]

Answer:

<em>The correct option is A) DNA → RNA → protein</em>

Explanation:

Central Dogma can be described as the process under which the processes of transcription and translation are focused. It is the process by which particular parts of DNA or particular genes make up the specified proteins which are required.

The conversion of DNA into RNA is known as transcription. This process occurs in the nucleus. The conversion of mRNA into proteins is termed as translation. This process occurs in the ribosomes of the cytoplasm.

7 0
3 years ago
Determine the empirical formulas for compounds with the following percent compositions:
White raven [17]

Answer: a)  CS_2

b) CH_2O

Explanation:

a) If percentage are given then we are taking total mass is 100 grams.

So, the mass of each element is equal to the percentage given.

Mass of C = 15.8g

Mass of S= 84.2 g

Step 1 : convert given masses into moles.

Moles of C =\frac{\text{ given mass of C}}{\text{ molar mass of C}}= \frac{15.8g}{12g/mole}=1.32moles

Moles of S=\frac{\text{ given mass of S}}{\text{ molar mass of S}}= \frac{84.2g}{32g/mole}=2.63moles

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For C = \frac{1.32}{1.32}=1

For S =\frac{2.63}{1.32}=2

The ratio of C  : S = 1:2

Hence the empirical formula is CS_2

b) Mass of C= 40 g

Mass of H= 6.7 g

Mass of O = 53.3 g

Step 1 : convert given masses into moles.

Moles of C =\frac{\text{ given mass of C}}{\text{ molar mass of C}}= \frac{40g}{12g/mole}=3.33moles

Moles of H =\frac{\text{ given mass of H}}{\text{ molar mass of H}}= \frac{6.7g}{1g/mole}=6.7moles

Moles of O =\frac{\text{ given mass of O}}{\text{ molar mass of O}}= \frac{53.3g}{16g/mole}=3.33moles

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For C = \frac{3.33}{3.33}=1

For H = \frac{6.7}{3.33}=2

For O =\frac{3.33}{3.33}=1

The ratio of C : H: O= 1 :2: 1

Hence the empirical formula is CH_2O

5 0
3 years ago
How many helium atoms are in a 12.0 g sample?
lakkis [162]
The correct answer is 2.99 helium atoms.


I hoped this helped!
8 0
3 years ago
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