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3 years ago

Explain what happens to the light ray when it travels through air and then into water

Chemistry

2 answers:

NemiM [27]3 years ago

6 0

A Change of Course. Light travels faster through air than it does through a denser substance, such as water or glass.

So, when light rays travel through air and meet the surface of the denser substance, they are suddenly slowed down.

When this happens, the light rays bend.

Mariulka [41]3 years ago

3 0

the light reflects through the glass therefore it looks different

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Give the result of the following expression with the correct number of significant figures

Marianna [84]

84 m/s x 31.221 s = 2600 m
-rounded from 2622.564 m because 84 m/s has only two significant figures

4 0

3 years ago

Yeast converts glucose to ethanol and carbon dioxide during a process known as anaerobic fermentation. The chemical reaction is

Korolek [52]

Answer:

102g

Explanation:

To find the mass of ethanol formed, we first need to ensure that we have a balanced chemical equation. A balanced chemical equation is where the number of atoms of each element is the same on both sides of the equation (reactants and products). This is useful as only when a chemical equation is balanced, we can understand the relationship of the amount (moles) of reactant and products, or to put it simply, their relationship with one another.

In this case, the given equation is already balanced.

$\tex{C_6H_{12}O_6} \longrightarrow 2 \ C_2H_6O + 2 \ CO_2$

From the equation, the amount of ethanol produced is twice the amount of yeast present, or the same amount of carbon dioxide produced. Do note that amount refers to the number of moles here.

Mole= Mass ÷Mr

Mass= Mole ×Mr

Method 1: using the mass of glucose

Mr of glucose

= 6(12) +12(1) +6(16)

= 180

Moles of glucose reacted

= 200 ÷180

= $\frac{10}{9}$ mol

Amount of ethanol formed: moles of glucose reacted= 2: 1

Amount of ethanol

= $2(\frac{10}{9} )$

= $\frac{20}{9}$ mol

Mass of ethanol

= $\frac{20}{9} \times[2(12)+6+16]$

= $\frac{20}{9}(46)$

= 102 g (3 s.f.)

Method 2: using mass of carbon dioxide produced

Mole of carbon dioxide produced

= 97.7 ÷[12 +2(16)]

= 97.7 ÷44

= $\frac{977}{440}$ mol

Moles of ethanol: moles of carbon dioxide= 1: 1

Moles of ethanol formed= $\frac{977}{440}$ mol

Mass of ethanol formed

= $\frac{977}{440} \times[2(12)+6+16]$

= 102 g (3 s.f.)

Thus, 102 g of ethanol are formed.

Additional:

For a similar question on mass and mole ratio, do check out the following!

brainly.com/question/1685725

8 0

2 years ago

A 420 mL sample of a 0.100 M formate buffer, pH 3.75, is treated with 7 mL of 1.00 M KOH. What is the pH following this addition

Art [367]

Answer: The pH of the resulting solution will be 3.60

Explanation:

Molarity is calculated by using the equation:

$\text{Molarity}=\frac{\text{Moles}}{\text{Volume}}$ ......(1)

We are given:

Molarity of formic acid = 0.100 M

Molarity of potassium formate = 0.100 M

Volume of solution = 420 mL = 0.420 L (Conversion factor: 1 L = 1000 mL)

Putting values in equation 1, we get:

$\text{Moles of formic acid}=(0.100mol/L\times 0.420L)=0.0420mol$

$\text{Moles of potassium formate}=(0.100mol/L\times 0.420L)=0.042mol$

Molarity of KOH = 1.00 M

Volume of solution = 7 mL = 0.007 L

Putting values in equation 1, we get:

$\text{Moles of KOH}=(1mol/L\times 0.007L)=0.007mol$

The chemical equation for the reaction of formic acid and KOH follows:

$HCOOH+KOH\rightleftharpoons HCOOK+H_2O$

I: 0.042 0.007 0.042

C: -0.007 -0.007 +0.007

E: 0.035 - 0.049

Volume of solution = [420 + 7] = 427 mL = 0.427 L

To calculate the pH of the acidic buffer, the equation for Henderson-Hasselbalch is used:

$pH=pK_a+ \log \frac{\text{[conjugate base]}}{\text{[acid]}}$ .......(2)

Given values:

$[HCOOK]=\frac{0.049}{0.427}$

$[HCOOH]=\frac{0.035}{0.427}$

$pK_a=3.75$

Putting values in equation 2, we get:

$pH=3.75-\log \frac{(0.049/0.427)}{(0.035/0.427)}\\\\pH=3.75-0.146\\\\pH=3.60$

Hence, the pH of the resulting solution will be 3.60

6 0

3 years ago

What will happen if you weighed out a quantity of beans

Ostrovityanka [42]

Answer:

When we weigh beans in this mass ratio, we must obtain the same number of beans.Explanation:

Nothing will happen

3 0

3 years ago

A gas sample occupies 5.38L at 36.0C. what is its temperature if volume is changed to 4.86L

Alina [70]

Answer: 2.5°C

Explanation:

Initial volume V1 = 5.38 liters

Initial temperature T1 = 36.0°C

Convert temperature in Celsius to Kelvin

(32°C + 273= 305K)

Final temperature T2 = ?

Final volume V2 = 4.68 liters

According to Charle's law, the volume of a fixed mass of a gas is directly proportional to the temperature.

Thus, Charles' Law is expressed as: V1/T1 = V2/T2

5.38/305 = 4.86/T2

To get the value of T2, cross multiply

5.38 x T2 = 4.86 x 305

5.38T2 = 1482.3

Divide both sides by 5.38

5.38T2/5.38 = 1482.3/5.38

T2 = 275.5K

Convert 275.5K to Celsius

(275.5K - 273K = 2.5°C)

Thus, the final temperature is 2.5°C

6 0

3 years ago