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vagabundo [1.1K]
3 years ago
11

Betty turned 71 this year but in three more years she will be twice as old as her daughter. How old is her daughter now

Mathematics
1 answer:
Liono4ka [1.6K]3 years ago
4 0

Answer: Betty's daughter is 34 years old now.

Step-by-step explanation:

So Betty is currently 71. In three years, she will be 74. So she will be twice as old as her daughter at the age of 74. To find out how old Betty's daughter is in 3 years, I will divide 74 by 2, which is 37 (74/2). Finally, I will subtract the original 3 years from the 37 years of age of Betty's daughter, and I will get my answer for how old Betty's daughter is, which is 34 years old.

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c. y = -4x

Step-by-step explanation:

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What is 4/7 ÷ 6/9 showing the work
RSB [31]
First flip the second fraction

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Suppose that a wall is constructed from concrete blocks where a block is a normal random variable with mean 11 kg and standard d
Artemon [7]

Answer:

The value for <em>k</em> is about k = 11.093kg.

Step-by-step explanation:

To answer this question, that is, P(x<k) = 0.85, we can use the standardized value for a raw score, or the formula for obtaining z-scores:

\\ z = \frac{x - \mu}{\sigma} [1]

Where

\\ x is the raw score.

\\ \mu is the population mean.

\\ \sigma is the population standard deviation.

In this case, we are asking to find a value x = k, so that 85% of the blocks have weights less than k (kg).

We have also to use the values for the <em>cumulative standard normal distribution</em> with \\ \mu = 0 and \\ \sigma = 1 to find the value of z that corresponds to a probability of 0.85.

First step: find the z that corresponds to the probability of 0.85.

To use the formula [1], as we previously mentioned, we first need to find the value of <em>z</em> that corresponds to a probability of 0.85 using the <em>cumulative standard normal distribution table</em> (available in any Statistics books or on the Internet). Then, for a cumulative probability of 0.85, the corresponding value for z = 1.03 (approximately).

Second step: solve the formula [1] for x.

Solving this formula for x, we have:

\\ z = 1.03

\\ \mu = 11kg

\\ \sigma = 0.09kg

Then (without units):

\\ z = \frac{x - \mu}{\sigma}

\\ 1.03 = \frac{x - 11}{0.09}

\\ 1.03*0.09 = x - 11

\\ (1.03*0.09) + 11 = x

So

\\ x = (1.03*0.09) + 11

\\ x = 0.0927 + 11

\\ x = 11.0927 \approx 11.093 = k

Thus, this value for x = 11.093 equals the value for k (x = k) so that

\\ P(x

Then

\\ P(x or

\\ P(x

We can see the graph below showing this value of k = 11.093kg for which 85% of the blocks have weights less that it (x = k = 11.093kg).  

4 0
3 years ago
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oee [108]

I think PT=2.5

becuz the formula I used is pt X rt = st X qt

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