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The initial population of a town in the year 2010 was 20 000. By 2014, the population had grown exponentially to 32 500 people.

stiv31 [10]

Answer:

P = 20000×1.625^(n/4)

Step-by-step explanation:

An exponential equation can be written using the given data:

value = (initial value)×(growth factor in period)^(n/(period))

Here, the growth is by a factor of 32500/20000 = 1.625, and the period is 4 years. Then your exponential equation is ...

P = 20000×1.625^(n/4)

3 0

3 years ago

Liliana is making a vase with a circular base. She wants the area of the base to be between 135 cm2 and 155 cm2. Which circle co

Umnica [9.8K]

Answer:

(b) Circle C is shown. Line segment A C is a radius with length 7 centimeters.

Step-by-step explanation:

Given

$Minimum\ Area = 135cm^2$

$Maximum\ Area = 155cm^2$

$\pi = 3.14$

Required

Which circle could she use

To do this, we simply calculate the areas of all the given circles

The area of a circle is:

$Area = \pi r^2$

Where

$r = radius$

$a.\ r = 6cm$

The area is calculated as thus:

$Area = \pi r^2$

$Area = 3.14 * (6cm)^2$

$Area = 3.14 * 36cm^2$

$Area = 114.04cm^2$

$b.\ r = 7cm$

The area is calculated as thus:

$Area = \pi r^2$

$Area = 3.14 * (7cm)^2$

$Area = 3.14 * 49cm^2$

$Area = 153.86cm^2$

$c.\ r = 8cm$

The area is calculated as thus:

$Area = \pi r^2$

$Area = 3.14 * (8cm)^2$

$Area = 3.14 * 64cm^2$

$Area = 200.96cm^2$

$d.\ r = 9cm$

The area is calculated as thus:

$Area = \pi r^2$

$Area = 3.14 * (9cm)^2$

$Area = 3.14 * 81cm^2$

$Area = 254.34cm^2$

From the calculations above; only the circle in option (b) has an area within the required range of 135 to 155cm^2

6 0

3 years ago

Read 2 more answers

Help pls with math lotsss of points!!!

sveticcg [70]

Answer:

5x^2+22x-12 x cannot be -5, -4, -2

(x+5)(x+4)(x+2)

Step-by-step explanation:

In order to solve this, your denominator must be the same. Let's start by writing out the two different quadratic formulas:

x^2 + 6x + 8 <-- This should factor out to (x+4)(x+2)

x^2 + 7x + 10 <-- This should factor out to (x+5)(x+2)

Now that you have factored out the two quadratics, plug them into the equation.

5x - 3

(x+4)(x+2) (x+5)(x+2)

Now as we know, -2 cannot be x because it will turn the entire equation undefined. Multiple top and bottom with (x+5) on the right side and (x+4) on the left side.

5x (x+5) - 3(x+4)

(x+5)(x+4)(x+2) (x+5)(x+4)(x+2)

Focus on the top. 5x(x+5) will turn out to be 5x^2+25x. 3(x+4) will turn out to be 3x+12. Combine the two equations because now they are equal to each other and do the subtraction:

5x^2+25x - (3x+12) = 5x^2+22x-12 x cannot be -5, -4, -2

(x+5)(x+4)(x+2) (x+5)(x+4)(x+2)

4 0

2 years ago

I need help with all the ones that don't have answers.

zlopas [31]

- What two consecutive odd integers have a sum of 48?

23 + 25 = 48

- Two negative consecutive integers have a sum of -45. What are the integers?

-22 + -23

- The sum of two consecutive integers 75. What are the two integers?

37 + 38 = 75

- What three consecutive odd integers have a sum of 81?

25 + 27 + 29 = 81

Hope I could help! Have a good one. I believe that is all of the unanswered questions. If I missed one, let me know!

7 0

3 years ago

PLEASE HELP ASAP is this relationship linear, exponential, or neither?

NeX [460]

Answer:

neither

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7 0

3 years ago