<span>Planets closest approach to the sun is associated with the term perihelion. </span>
Answer:
Normal daughters and Hemophiliac son
Explanation:
Females exhibit hemophilia and colorblindness in homozygous genotype only.
The genotype of hemophiliac woman= X^hX^h
The genotype of colorblind man= X^cY
A cross between X^hX^h and X^cY would produce progeny in the following phenotype ratio= 1 Normal but carrier daughters:1 Hemophiliac son
Options for the question are not given. They are as follows :
A. Mate them and see what color the offspring are—that will be the dominant color
B. Mate them and see what color the offspring are—the other will be the dominant color
C. Mate them, and then mate their offspring to see what color the next generation is
D. Mate them together, and then mate their offspring to see what color the next generation is—the other color will be the dominant color
Answer:
A. Mate them and see what color the offspring are—that will be the dominant color
Explanation:
Out of the two colors, one will be recessive and one will be dominant. Recessive color will be homozygous since it is only expressed in homozygous condition. It is also given that in this cross the dominant color is also in homozygous condition.
When the guinea pigs mate, the resulting progeny will obtain one dominant allele from the dominant color parent and one recessive allele from the recessive color parent. The progeny will be heterozygous and show the dominant phenotype since the dominant allele will mask the recessive allele. Thus, the color which is visible in their offspring will be the dominant color.
Ÿöu have to add 8 10 times the. You would get 80
Answer:
10
Explanation:
The cell cycle is composed of three states: interphase, cell division and resting.
The interphase is composed of 3 phases: G1, S and G2 (in this order). During this state the cell prepares itself for cell division. As part of the preparation the cell duplicates all its genetic material, that is, all its chromosomes. This duplication is done during the phase S.
During the meiotic cell division (composed of meiosis 1 and meiosis 2) a single diploid mother cell (with duplicated chromosomes) produces four haploid daughter cells. the meiosis 1 produces two haploid cells with duplicated chromosomes, and the meiosis 2 produces 4 haploid cells with normal chromosomes (no duplicated).
If a germ-line cell from a frog contains 10 picograms of DNA during G1, then this cell will have 20 picograms of DNA before the product of the first meiotic division, and will have 10 picograms at the begining of the meiosis 2 (i.e prophase II)
