3(x – 5) = 2(x – 5) + x solve for x and number of soultions
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Let 
. Then 
and 
are two fundamental, linearly independent solution that satisfy
Note that
, so that 
. Adding 
doesn't change this, since 
.
So if we suppose
then substituting
would give
To make sure everything cancels out, multiply the second degree term by
, so that
Then if
, we get
as desired. So one possible ODE would be
(See "Euler-Cauchy equation" for more info)
Note that
So if we suppose
then substituting
To make sure everything cancels out, multiply the second degree term by
Then if
as desired. So one possible ODE would be
(See "Euler-Cauchy equation" for more info)