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Musya8 [376]
3 years ago
9

HELPPPPPPPPPP!!!!!

Mathematics
1 answer:
Thepotemich [5.8K]3 years ago
5 0

Answer:

Local maximum: approx. (1, 8.08), Local minima: approx. (-2, -7.67) and (3, 2.75)

Step-by-step explanation:

Local maxima are the various maxima in the function and the local minima are the various minima in the function. Knowing that, we can deduce that the answer is "Local maximum: approx. (1, 8.08), Local minima: approx. (-2, -7.67) and (3, 2.75)" or C.

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To join the game club, you must pay $7 a month plus
ivanzaharov [21]

Answer: Total cost/month = 7 + 3x

Step-by-step explanation:

This is only the total cost per month that is why it is only 7 and 3x since the number of downloaded games is not given.

I'm not sure about my answer but I hope that it helps.

8 0
2 years ago
A jar contains 8 marbles numbered 1 through 8. an experiment consists of randomly selecting a marble from the jar, observing the
zepelin [54]
There are 8 possible outcomes for a marble being drawn and numbered. 
{1,2,3,4,5,6,7,8}
There are 4 possible outcomes for a card being selected from a standard deck.
{ <span>hearts, diamonds, clubs, spades}
So the number of outcomes in the sample space would be 8 x 4 = 32.

In the event "an even number is drawn", there are only 4 possible outcomes for a marble being drawn, {2,4,6,8}, whereas there are still 4 possible outcomes for a suit. So the number of outcomes in the event is 4 x 4 = 16.

</span><span>In the event "a number more than 2 is drawn and a red card is drawn", there are 6 possible outcomes for the marble being drawn, {3,4,5,6,7,8}, whereas there are only two possible suits for a card being selected as red, {heart, diamond}. So the number of outcomes in this event is 6 x 2 = 12.

In the event </span><span>"a number less than 3 is drawn or a club is not drawn", the number drawn could be 1 or 2 whereas a spade/heart/diamond could be selected. So the number of outcomes is 2 x 3 = 6.</span><span>

</span>
3 0
3 years ago
What is the value of m?<br> m3 = 64
uranmaximum [27]

Answer

m=4

Step-by-step explanation:

3 0
3 years ago
Please help someone
DiKsa [7]

The first equation is x = -1

The second and third equations are no solution

The third equation is all rel numbers.


We can tell each one by solving them. In the first one, you get the following.


4 + x = -8x - 5 ----> Add 8x to both sides

4 + 9x = -5 ----> Subtract 4 from both sides

9x = -9 ----> Divide both sides by 9

x = -1


For the middle two, when you attempt to solve, you get untrue statements. This shows there are no solutions. See the example below.


7 + 2x = 2x - 7 ----> Subtract 2x from both sides

7 = -7 (UNTRUE)


And for the last one, each term cancels out, which shows that we have all real solutions.


-3x + 3 = 3( 1 - x) ----> Distribute the 3

-3x + 3 = 3 - 3x ----> Add 3x to both sides

3 = 3 (TRUE)

8 0
3 years ago
<img src="https://tex.z-dn.net/?f=f%28x%29%20%3D%20%20%5Csqrt%7Bx%7D%20" id="TexFormula1" title="f(x) = \sqrt{x} " alt="f(x) =
Georgia [21]

Answer:    \dfrac{1}{2\sqrt x}

<u>Step-by-step explanation:</u>

\lim_{h \to 0} f(x)=\dfrac{f(x+h)-f(x)}{h}

f(x) = \sqrt x\\

f(x+h) = \sqrt{x+h}

\lim_{h \to 0} f(x)=\dfrac{\sqrt{x+h}-\sqrt x}{h}

                   =\dfrac{\sqrt{x+h}-\sqrt x}{h}\bigg(\dfrac{\sqrt{x+h}+\sqrt x}{\sqrt{x+h}+\sqrt x}\bigg)

                   =\dfrac{(x + h)-(x)}{h(\sqrt{x+h}+\sqrt x)}

                   =\dfrac{h}{h(\sqrt{x+h}+\sqrt x)}

                   =\dfrac{1}{\sqrt{x+h}+\sqrt x}

                  =\dfrac{1}{\sqrt{x+0}+\sqrt x}

                  =\dfrac{1}{2\sqrt x}

4 0
3 years ago
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