Answer:
a) y= -18x +486
b)
10, y= 306
11, y= 288
12, y= 270
13, y= 252
14, y= 234
15, y= 216
Step-by-step explanation:
I hope this helped! brainliest pls?
<3
Answer:
1.024x10^17
Step-by-step explanation:
5^5(16^2x5^3)^3
find the 5^5
3125(16^2x5^3)^3
distribute the power of 3 into the parentheses
3125(16^6x5^9)
multiply
3125(16777216x1953125)
1.024x10^17
Answer:
75% confidence interval is 91.8±16.66. That is between 75.1 and 108.5 pounds.
Step-by-step explanation:
The question is missing. It is as follows:
Adult wild mountain lions (18 months or older) captured and released for the first time in the San Andres Mountains had the following weights (pounds): 69 104 125 129 60 64
Assume that the population of x values has an approximately normal distribution.
Find a 75% confidence interval for the population average weight μ of all adult mountain lions in the specified region. (Round your answers to one decimal place.)
75% Confidence Interval can be calculated using M±ME where
- M is the sample mean weight of the wild mountain lions (
)
- ME is the margin of error of the mean
And margin of error (ME) of the mean can be calculated using the formula
ME=
where
- t is the corresponding statistic in the 75% confidence level and 5 degrees of freedom (1.30)
- s is the standard deviation of the sample(31.4)
Thus, ME=
≈16.66
Then 75% confidence interval is 91.8±16.66. That is between 75.1 and 108.5
Answer:
C 47.12 L
Step-by-step explanation:
1 gallon = 3.8 liters
12.4 gallons = x
Cross Multiply
= 12.4 × 3.8
47.12 liters
Option C is correct
Answer:
Your score is 100.
Step-by-step explanation:
If you have -300 and add +300 you will end up with 0 because when a positive and a negative that are equal cancel each other out. So if you add +300 to -300 you get 0 but its 400 so 300 + 100 is 400 so you have +100 left. : )