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Tasya [4]
3 years ago
8

A triangle with base 6. and height 3 in. Whats the answer and please show work

Mathematics
2 answers:
katrin [286]3 years ago
6 0
The formula for a triangle to find its area is A=1/2bh.
So you are trying to find the area...So you equation would be A=1/2×6×3 so I am going to multiply 6×3 first which equals 18 then you can either multiply by
.5 or divide by 2 (I chose to multiply) so I multipled 18× .5 and got 9. So 9 is your area
(Sorry if this is confusing)

I hope I helped :) <3
motikmotik3 years ago
4 0
How you find the area of a triangle is base × height ÷ 2. So the equation would be 6×3=18 18÷2=9, so the answer is 9. Hope this helped!
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Step-by-step explanation:

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2 years ago
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saw5 [17]
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3 0
3 years ago
Last year there were 120 students in choir. This year, 30% more students took choir. How many students are taking choir this yea
hjlf

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Step-by-step explanation:

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7 0
3 years ago
​Find all roots: x^3 + 7x^2 + 12x = 0 <br> Show all work and check your answer.
Aliun [14]

The three roots of x^3 + 7x^2 + 12x = 0 is 0,-3 and -4

<u>Solution:</u>

We have been given a cubic polynomial.

x^{3}+7 x^{2}+12 x=0

We need to find the three roots of the given polynomial.

Since it is a cubic polynomial, we can start by taking ‘x’ common from the equation.

This gives us:

x^{3}+7 x^{2}+12 x=0

x\left(x^{2}+7 x+12\right)=0   ----- eqn 1

So, from the above eq1 we can find the first root of the polynomial, which will be:

x = 0

Now, we need to find the remaining two roots which are taken from the remaining part of the equation which is:

x^{2}+7 x+12=0

we have to use the quadratic equation to solve this polynomial. The quadratic formula is:

x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}

Now, a = 1, b = 7 and c = 12

By substituting the values of a,b and c in the quadratic equation we get;

\begin{array}{l}{x=\frac{-7 \pm \sqrt{7^{2}-4 \times 1 \times 12}}{2 \times 1}} \\\\{x=\frac{-7 \pm \sqrt{1}}{2}}\end{array}

<em><u>Therefore, the two roots are:</u></em>

\begin{array}{l}{x=\frac{-7+\sqrt{1}}{2}=\frac{-7+1}{2}=\frac{-6}{2}} \\\\ {x=-3}\end{array}

And,

\begin{array}{c}{x=\frac{-7-\sqrt{1}}{2}} \\\\ {x=-4}\end{array}

Hence, the three roots of the given cubic polynomial is 0, -3 and -4

4 0
3 years ago
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Phantasy [73]

Answer:

I think it's D

Step-by-step explanation:

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3 0
3 years ago
Read 2 more answers
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