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natulia [17]
4 years ago
5

Evaluate a(a-b); use a=3, and b=1​

Mathematics
1 answer:
scoundrel [369]4 years ago
6 0

Answer:

6

Step-by-step explanation:

a(a-b)

Let a =3 and b=1

3(3-1)

parentheses first

3(2)

6

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Find the zeros of the quadratic equation-<br> v(5v-7)=0
vovangra [49]

Answer:

Step-by-step explanation:

v(5v-7)=0

We multiply parentheses

5v^2-7v=0

a = 5; b = -7; c = 0;

Δ = b2-4ac

Δ = -72-4·5·0

Δ = 49

The delta value is higher than zero, so the equation has two solutions

We use following formulas to calculate our solutions:

v1 = −b−√Δ/2a

v2 = -b+√Δ/2a

√Δ = √49 = 7

v1 = -(−7)−7/2*5 = 0/10 = 0

v2 = -(−7)+7/2*5 = 14/10 =  1+2/5

3 0
3 years ago
What is the answer for this question
emmasim [6.3K]
The answer is 2/9. you just cross multiply then multiply straight across
4 0
3 years ago
Read 2 more answers
Simplify. (-5) • (7) - (6) • (-2)
andrew11 [14]
Multiply (-5) and (7) together to get -35
Then multiply (6) and (-2) together to get -12

Finally multiply -35 and -12 together to get 420

So your answer to this is 420

Hope this helped :)
Have a good day
8 0
4 years ago
Which represents the solutions of the system of equations
ad-work [718]

Answer:

(1,1)

Step-by-step explanation:

Since y=x, we can say x=x^2-x+1. This means x^2-2x+1=0. x=1, y=1, thus your solution is (1,1).

7 0
4 years ago
Pls help I will give brainliest<br> I need help with question#15
nevsk [136]

Answer: I think it’s c

Step-by-step explanation:

8 0
3 years ago
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